Question

我有一系列房子，里面有一系列房间。

每个房间，房屋和街道都有唯一的ID（例如：如果房屋1中的房间ID为1..4，房屋2中的房间ID为5..9）

var street = {
    id = 1,
    streetname = 'stack street',
    houses = [
        {
            id: 1,
            type: 'brick'
            rooms: [
                {
                    id: 1,
                    color: 'blue'
                }, ... a bunch more
            ]
        }, ... a bunch more
    ]
}

有没有像arr.findIndex（）这样的简单解决方案：
1）在给定房间ID的情况下，返回数组房屋中房屋的索引，以及该房屋数组中房屋的索引。
2）给定房间ID，退还其所在的房子
3）给定房间ID，返回房间对象

Answer 1

对于房间ID 7：

1）

int houseIndex = street.houses.findIndex(house => house.rooms.find(room => room.id == 7));
int roomIndex = street.houses.find(house => house.rooms.find(room => room.id == 7)).rooms.findIndex(room => room.id == 7)

2）

var houseObject = street.houses.find(house => house.rooms.find(room => room.id == 7))

3）

var roomObject = street.houses.find(house => house.rooms.find(room => room.id == 7)).rooms.find(room => room.id == 7)

Answer 2

1）Private Sub SplitDateAndTime() Dim input = "11/9/201812:52:53 AM" Dim d As DateTime = DateTime.ParseExact(input, "M/d/yyyyhh:mm:ss tt", CultureInfo.InvariantCulture) Dim dateOnly As String = d.ToShortDateString Dim timeOnly As String = d.ToLongTimeString Debug.Print($"The date is {dateOnly} and the time is {timeOnly}") 'result The date is 11/9/2018 and the time is 12:52:53 AM End Sub是一个简单的解决方案，但是您需要再次使用数组函数来扫描房屋检查回调中的房间：

findIndex()

2）与var houseIndex = street.houses.findIndex(h => h.rooms.some(r => r.id === roomId));相同：

find()

或如果先前的索引查找到位，则使用其结果：

var house = street.houses.find(h => h.rooms.some(r => r.id === roomId));

3）将房屋房间层次化为普通房间列表，并在其中搜索所需的房间：

var house = street.houses[houseIndex];

在数组数组中按ID查找对象的索引

2 个答案: