Question

我正在尝试在Django中实现以下示例，并列出表中的所有进程，但是我很难在模板中显示信息。我在python文件中运行了这段代码，它输出多个列表（每个进程一个），如下所示：

import psutil
for p in psutil.process_iter(attrs=['pid', 'username', 'status', 'cpu_percent', 'memory_percent', 'memory_info', 'name']):
    process_info = [p.pid, p.info['username'], p.info['status'], p.info['memory_info'].rss, p.info['cpu_percent'], p.info['memory_percent'], p.info['name']]
    print(process_info)

[1, 'root', 'sleeping', 9142272, 0.0, 0.009034306321108227, 'systemd']
[2, 'root', 'sleeping', 0, 0.0, 0.0, 'kthreadd']
[3, 'root', 'idle', 0, 0.0, 0.0, 'rcu_gp']
[4, 'root', 'idle', 0, 0.0, 0.0, 'rcu_par_gp']
[5, 'root', 'idle', 0, 0.0, 0.0, 'kworker/0:0-events']
[6, 'root', 'idle', 0, 0.0, 0.0, 'kworker/0:0H-kblockd']
[8, 'root', 'idle', 0, 0.0, 0.0, 'mm_percpu_wq']

如何处理所有这些单独的列表并将其显示为表格行？

更新：这是我在views.py

中的请求

def processes(request):
    for p in psutil.process_iter(attrs=['pid', 'username', 'status', 'cpu_percent', 'memory_percent', 'memory_info', 'name']):
    process_info = [p.pid, p.info['username'], p.info['status'], p.info['memory_info'].rss, p.info['cpu_percent'], p.info['memory_percent'], p.info['name']]


    context_processes = {'process_info': process_info }
    return render(request, 'lwp_admin/processes.html', context_processes )

以下是模板中用于输出的Django代码：

<table class="table table-bordered table-responsive table-striped table-condensed">
                  <thead class="bg-green-gradient">
                    <tr>
                        <th scope="col" class="col-xs-1 text-center">PID</th>
                        <th scope="col" class="col-xs-1 text-center">Owner</th>
                        <th scope="col" class="col-xs-1 text-center">Status</th>
                        <th scope="col" class="col-xs-1 text-center">RSS</th>
                        <th scope="col" class="col-xs-1 text-center">CPU usage (%)</th>
                        <th scope="col" class="col-xs-1 text-center">MEM usage (%)</th>
                        <th scope="col" class="col-xs-3 text-center">Command</th>
                    </tr>
                  </thead>
                  <tbody>
                      {% for proc in context_processes.process_info %}
                      <tr>
                          <td>{{ proc }}</td>
                      </tr>
                      {% endfor %}
                  </tbody>
</table>

Answer 1

修改：基于新信息 您已经创建了上下文字典，并将其分配给context_processes。您不会将字典的字典传递给render()。

将您的查看代码更改为：

return render(request, 'lwp_admin/processes.html', context_processes )

在模板中，您可以像这样遍历传递的上下文

<tr>
    {% for proc in process_info %}
        <td>{{ proc }}</td>
    {% endfor %}
</tr>

对于参考，在如何将上下文传递到模板方面可能仍然有帮助

您是否将生成的字典添加到视图上下文中？您可以在将view字典传递到模板之前，将其附加到view方法中。

如果视图是函数，则只需在构建上下文时将其传递给render(request, template, context)函数即可。 https://docs.djangoproject.com/en/2.1/topics/http/views/

如果您使用的是基于类的视图，则可以根据要继承的基类get_context_data()重写或添加View方法。 see example https://docs.djangoproject.com/en/2.1/topics/class-based-views/generic-display/#adding-extra-context

在模板中，您可以通过保存到模板的键访问上下文值。例如

{{ name }}
{{ pid }}
{{ username }}

请参阅模板文档https://docs.djangoproject.com/en/2.1/topics/templates/#variables 希望有帮助

Answer 2

好的，最后我设法解决了这个问题：

下面列出了views.py代码

def processes(request):
proc_objects = []
for p in psutil.process_iter(attrs=['pid', 'username', 'cpu_percent', 'memory_percent', 'memory_info', 'name']):
    process_info = [p.pid, p.info['username'], round(p.info['memory_info'].rss), p.info['cpu_percent'],p.info['memory_percent'], p.info['name']]
    proc_objects.append(process_info)
    td_buttons = ['hangup', 'terminate', 'kill']

context_processes = {'proc_objects': proc_objects, 'td_buttons': td_buttons }
return render(request, 'lwp_admin/processes.html', context_processes)

用于此的模板代码如下：

 <table class="table table-bordered table-responsive table-striped table-condensed">
              <thead class="bg-maroon-gradient">
                <tr>
                    <th scope="col" class="col-xs-1 text-center">PID</th>
                    <th scope="col" class="col-xs-1 text-center">Owner</th>
                    <th scope="col" class="col-xs-1 text-center">RSS</th>
                    <th scope="col" class="col-xs-1 text-center">CPU usage (%)</th>
                    <th scope="col" class="col-xs-1 text-center">MEM usage (%)</th>
                    <th scope="col" class="col-xs-3 text-center">Command</th>
                    <th scope="col" class="text-center">Hang Up</th>
                    <th scope="col" class="text-center">Terminate</th>
                    <th scope="col" class="text-center">Kill</th>
                </tr>
              </thead>
              <tbody>
              {% for process_info in proc_objects %}
                  <tr class="text-center">
                      {% for proc in process_info %}
                          <td>{{ proc }}</td>
                      {% endfor %}
                      <td><button type="button" class="btn btn-primary">Hang Up</button></td>
                      <td><button type="button" class="btn btn-warning">Terminate</button></td>
                      <td><button type="button" class="btn btn-danger">Kill</button></td>
                  </tr>
              {% endfor %}
              </tbody>
          </table>

此输出为： [ process list[1]

在Django模板中显示进程列表

2 个答案: