当我将mutil数据库与相关对象一起使用时，找不到正确的表。 ta是acc数据库中的表名。 tb也是贸易数据库中的表名。 ta记录： 身份证名 1个名字
tb记录： 身份证名 1吨名称
$em=$this->getDoctrine()->getRepository(ta::class,'customer');
$ta=$em->find(2);//now ,it can fetch the data,and the data is right
$tb=$ta->getTbTable();
$szName=$tb->getName(); //i want to get the tb record,it will throw an exception :
............................................... 'acc.tb'不存在”
实际上，tb在贸易数据库中。
如何解决这些问题
<?php
namespace AppBundle\Entity;
use Doctrine\ORM\Mapping as ORM;
use Doctrine\ORM\Mapping\PrePersist;
use Doctrine\ORM\Mapping\PreUpdate;
use Doctrine\ORM\Mapping\HasLifecycleCallbacks;
use Symfony\Component\Validator\Constraints as Assert;
/**
* @ORM\Table(name="ta")
* @ORM\Entity(repositoryClass = "AppBundle\Entity\taRepository")
* @ORM\HasLifecycleCallbacks()
* @package AppBundle\Entity
*/
class ta {
/**
* @ORM\Column(type="integer",unique=true)
* @Assert\NotBlank(message="账号ID不能为空")
* @ORM\Id
*/
private $id;
/**
* @ORM\Column(type="string")
*/
private $name;
/**
* @ORM\ManyToOne(targetEntity="AppBundle\EntityTrade\tb")
* @ORM\JoinColumn(name="id",referencedColumnName="id")
*/
private $tb_table;
/**
* Set id.
*
* @param int $id
*
* @return ta
*/
public function setId($id)
{
$this->id = $id;
return $this;
}
/**
* Get id.
*
* @return int
*/
public function getId()
{
return $this->id;
}
/**
* Set name.
*
* @param string $name
*
* @return ta
*/
public function setName($name)
{
$this->name = $name;
return $this;
}
/**
* Get name.
*
* @return string
*/
public function getName()
{
return $this->name;
}
/**
* Set tbTable.
*
* @param \AppBundle\EntityTrade\tb|null $tbTable
*
* @return ta
*/
public function setTbTable(\AppBundle\EntityTrade\tb $tbTable = null)
{
$this->tb_table = $tbTable;
return $this;
}
/**
* Get tbTable.
*
* @return \AppBundle\EntityTrade\tb|null
*/
public function getTbTable()
{
return $this->tb_table;
}
}
<?php
namespace AppBundle\EntityTrade;
use Doctrine\ORM\Mapping as ORM;
use Doctrine\ORM\Mapping\PrePersist;
use Doctrine\ORM\Mapping\PreUpdate;
use Doctrine\ORM\Mapping\HasLifecycleCallbacks;
use Symfony\Component\Validator\Constraints as Assert;
/**
* @ORM\Table(name="tb")
* @ORM\Entity(repositoryClass = "AppBundle\EntityTrade\tbRepository")
* @ORM\HasLifecycleCallbacks()
* @package AppBundle\EntityTrade
*/
class tb {
/**
* @ORM\Column(type="integer",unique=true)
* @Assert\NotBlank(message="账号ID不能为空")
* @ORM\Id
*/
private $id;
/**
* @ORM\Column(type="string")
*/
private $name;
/**
* Set id.
*
* @param int $id
*
* @return tb
*/
public function setId($id)
{
$this->id = $id;
return $this;
}
/**
* Get id.
*
* @return int
*/
public function getId()
{
return $this->id;
}
/**
* Set name.
*
* @param string $name
*
* @return tb
*/
public function setName($name)
{
$this->name = $name;
return $this;
}
/**
* Get name.
*
* @return string
*/
public function getName()
{
return $this->name;
}
}
class defaultController{
public function indexAction(){
$em=$this->getDoctrine()->getRepository(ta::class,'customer');
$ta=$em->find(2);
$tb=$ta->getTbTable();
$szName=$tb->getName();
}
}
答案 0 :(得分：0)
它不能以这种方式工作。 Doctrine的EntityManager仅支持单个数据库内实体的管理，因此将不会在ta和tb之间建立跨数据库关系。有关更多信息，请参阅Doctrine Bug跟踪程序中的this issue。
但是，您的目标可以通过稍微不同的方式来实现。您不能在实体之间建立跨数据库关系，但是您当然可以存储将实体引用到不同数据库的ID。因此，您可以将所有跨数据库关系逻辑移动到存储库中。例如，假设每个数据库有2个EntityManager：$accEm数据库的acc和$tradeEm数据库的trade。请注意，您正在使用Symfony-可以将它们配置为DoctrineBundle配置，然后注入到服务中。
您将需要对代码进行一些更改：
ta.php ，我省略了大部分代码来表达需要进行的更改。
namespace AppBundle\Entity;
class ta
{
/**
* @ORM\Column(type="integer", nullable=true)
* @var int
*/
private $tb_table; // Notice that it is not a reference anymore, but simple integer
/**
* Set tbTable.
*
* @param \AppBundle\EntityTrade\tb|null $tbTable
*
* @return ta
*/
public function setTbTable(\AppBundle\EntityTrade\tb $tbTable = null)
{
// You can also consider updating this method to accept plain integers aswel
$this->tb_table = $tbTable instanceof \AppBundle\EntityTrade\tb ? $tbTable->getId() : null;
return $this;
}
/**
* Get tbTable.
*
* @return int|null
*/
public function getTbTable()
{
// Also notice that plain integer is returned, you may want to rename column and method names to reflect this change of column meaning
return $this->tb_table;
}
}
taRepository.php ，我也省略了大部分可能存在的代码
namespace AppBundle\Entity;
use Doctrine\ORM\EntityManager;
use Doctrine\ORM\EntityRepository;
class taRepository extends EntityRepository {
/**
* @var EntityManager
*/
private $tradeEm;
/**
* @param EntityManager $tradeEm
*/
public function setTradeEntityManader(EntityManager $tradeEm)
{
// It is required to pass instance of EntityManager for "trade" database here. It should be done via Symfony services configuration, please refer Symfony documentation on this topic if needed
$this->tradeEm = $tradeEm;
}
/**
* @param ta $ta
* @return \AppBundle\EntityTrade\tb|null
*/
public function getTbTable(ta $ta) {
// This method should be used instead of $ta::getTbTable()
$tbId = $ta->getTbTable();
if ($tbId === null) {
return null;
}
return $this->tradeEm->find(\AppBundle\EntityTrade\tb::class, $tbId);
}
}
defaultController.php
namespace AppBundle\Controller;
use Doctrine\ORM\EntityManager;
class defaultController
{
/**
* @var EntityManager
*/
private $tradeEm;
/**
* @param EntityManager $tradeEm
*/
public function __construct(EntityManager $tradeEm)
{
// Same as before, this should be instance of EntityManager for "trade" database
$this->tradeEm = $tradeEm;
}
public function indexAction()
{
$em = $this->getDoctrine()->getRepository(ta::class, 'customer');
$ta = $em->find(2);
// Notice that we're not receiving "trade" database entity directly, but using corresponding EntityManager instead
$tb = $this->tradeEm->getTbTable($ta);
if ($tb !== null) {
$szName = $tb->getName();
}
}
}