Question

如何仅保留唯一值

if (enabled) {
    ViewCompat.setBackgroundTintList(btn, getResources().getColorStateList(R.color.button_states)); // either use a single color, or a state_list color resource
} else {
    ViewCompat.setBackgroundTintList(btn, ColorStateList.valueOf(Color.GRAY));
}
// make sure we're always clickable
btn.setEnabled(true);
btn.setClickable(true);

我想实现这样的结果

<?php
header('Content-Type: application/json');

function super_unique($array,$key){
    $temp_array = [];
    foreach ($array as &$v) {
        if (!isset($temp_array[$v[$key]]))
        $temp_array[$v[$key]] =& $v;
    }
    $array = array_values($temp_array);
    return $array;

}

$arr = array();
$arr[0]['id'] = null; 
$arr[0]['name'] = 'John';

$arr[1]['id'] = 12; 
$arr[1]['name'] = 'John';

$arr[2]['id'] = null; 
$arr[2]['name'] = null; 

$arr[3]['id'] = 54; 
$arr[3]['name'] = 'Ammie'; 

$arr[4]['id'] = 23; 
$arr[4]['name'] = 'Martin'; 

$arr[5]['id'] = 54; 
$arr[5]['name'] = null; 

$arr[6]['id'] = 342; 
$arr[6]['name'] = 'Anna'; 

$arr[7]['id'] = 64; 
$arr[7]['name'] = 'Tom'; 

$arr[8]['id'] = 64; 
$arr[8]['name'] = null; 

$arr[9]['id'] = 364; 
$arr[9]['name'] = null; 

$arr[10]['id'] = null; 
$arr[10]['name'] = 'Piter'; 


$arr = super_unique($arr,'id');
$arr = super_unique($arr,'name');

$arr = array_values($arr);

echo json_encode($arr);

?>

使用Peter不会向我显示结果，而John给出的ID为空

如果id相同，则必须按名称检查并仅保留一个且不为null，如果唯一值为null，则仅保留null

喜欢的ID：364 空名称

以及名称我希望约翰ID是12

有什么建议吗？谢谢！

Answer 1

您可以按以下方式重写唯一方法：

//This function will get you the missing field from the array:
function getField($arr, $key, $value, $newKey) {
    foreach($arr as $e)
        if (($e[$key] == $value) && $e[$newKey])
            return $e[$newKey];
}

$res = array();
foreach($arr as $a) {
    if (!$a["id"] && !$a["name"])
        continue; // if both null ignore
    if (!$a["id"]) // if id missing go get it
        $a["id"] = getField($arr, "name", $a["name"], "id");
    if (!$a["name"]) // fill the name if missing
        $a["name"] = getField($arr, "id", $a["id"], "name");
    $res[] = $a; // as to result array
}

$r = array_map("json_decode", array_unique(array_map("json_encode", $res))); // remove all duplicate elements

这将打印出来：

echo json_encode(array_values($r));

[{"id":12,"name":"John"},{"id":54,"name":"Ammie"},{"id":23,"name":"Martin"},{"id":342,"name":"Anna"},{"id":64,"name":"Tom"},{"id":364,"name":null},{"id":null,"name":"Piter"}]

在多维数组中仅保留唯一元素

1 个答案: