Question

我是刚开始使用android构建应用程序，所以请原谅。

我的应用程序在后台时会收到通知，但在前台时却不会，我想同时获取两者的通知。

现在发生的是，当我在前台收到应用程序的通知时，该应用程序崩溃了。

我确实了解android在这两个事件处于两种不同状态时如何处理这两个事件，因此我必须修改onMessageReceived来处理该数据。这是我到目前为止所拥有的

MyFirebaseMessagingService.java

public class MyFirebaseMessagingService extends FirebaseMessagingService {

    @Override
    public void onMessageReceived(RemoteMessage remoteMessage) {
        super.onMessageReceived(remoteMessage);
        Log.d("msg", "onMessageReceived: " + remoteMessage.getData().get("message"));
        Intent intent = new Intent(this, MainActivity.class);
        intent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
        PendingIntent pendingIntent = PendingIntent.getActivity(this, 0, intent, PendingIntent.FLAG_ONE_SHOT);
        String channelId = "Default";
        NotificationCompat.Builder builder = new  NotificationCompat.Builder(this, channelId)
                .setSmallIcon(R.mipmap.ic_launcher)
                .setSound(RingtoneManager.getDefaultUri(RingtoneManager.TYPE_NOTIFICATION))
                .setContentTitle(remoteMessage.getNotification().getTitle()).setAutoCancel(true).setContentIntent(pendingIntent)
                .setContentText(remoteMessage.getNotification().getBody()).setAutoCancel(true).setContentIntent(pendingIntent);
        NotificationManager manager = (NotificationManager) getSystemService(NOTIFICATION_SERVICE);
        if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O) {
            NotificationChannel channel = new NotificationChannel(channelId, "Default channel", NotificationManager.IMPORTANCE_DEFAULT);
            manager.createNotificationChannel(channel);
        }
        manager.notify(0, builder.build());
    }

}

侧面问题：我不确定代码的这一部分是否正确manager.notify(0, builder.build());，据我了解，0是某种CHANNEL_ID，因此我不确定0是正确的值。

AndroidManifest.xml

<application
    android:allowBackup="true"
    android:icon="@mipmap/ic_launcher"
    android:label="@string/app_name"
    android:roundIcon="@mipmap/ic_launcher_round"
    android:supportsRtl="true"
    android:theme="@style/AppTheme">

    <activity android:name=".MainActivity">
        <intent-filter>
            <action android:name="android.intent.action.MAIN" />
            <category android:name="android.intent.category.LAUNCHER" />
        </intent-filter>
    </activity>

    <service
        android:name=".MyFirebaseMessagingService"
        android:stopWithTask="false">
        <intent-filter>
            <action android:name="com.google.firebase.MESSAGING_EVENT" />
        </intent-filter>
    </service>

</application>

这也是我的理解，为了使onMessageReceived处理send，我不需要使用notification而是使用data。所以我用php发送我的数据。

$notification = [
    'title' => $title,
    'body' => $message,
    //'icon' =>'myIcon',
    'vibrate' => 1,
    'sound' => 'default'
];

$fcmNotification = [
    'registration_ids' => $token,
    'data' => $notification
];

json_encode($fcmNotification));

Logcat

2018-12-31 12:36:26.416 22775-22850/com.domainname.main.domainname D/msg: onMessageReceived: null
2018-12-31 12:36:26.419 22775-22850/com.domainname.main.domainname E/AndroidRuntime: FATAL EXCEPTION: Firebase-MyFirebaseMessagingService
    Process: com.domainname.main.domainname, PID: 22775
    java.lang.NullPointerException: Attempt to invoke virtual method 'java.lang.String com.google.firebase.messaging.RemoteMessage$Notification.getBody()' on a null object reference
        at com.domainname.main.domainname.MyFirebaseMessagingService.onMessageReceived(MyFirebaseMessagingService.java:31)
        at com.google.firebase.messaging.FirebaseMessagingService.zzd(Unknown Source)
        at com.google.firebase.iid.zzc.run(Unknown Source)
        at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1133)
        at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:607)
        at com.google.android.gms.common.util.concurrent.zza.run(Unknown Source)
        at java.lang.Thread.run(Thread.java:762)

因此，在这一点上，我不确定问题是如何在MyFirebaseMessagingService.java中发送数据或代码。有什么想法吗？

已解决

好吧，我弄清楚了，这主要是我发送数据的方式。我必须将我的php更改为此

$notification = [
    'title' => $title,
    'body' => $message,
    //'icon' =>'myIcon',
    'vibrate' => 1,
    'sound' => 'default'
];

$extraNotificationData = [
    'title' => $title,
    'body' => $message,
    //'icon' =>'myIcon',
    'vibrate' => 1,
    'sound' => 'default'
];

$fcmNotification = [
    'registration_ids' => $token, //single token
    'notification' => $notification,
    'data' => $extraNotificationData
];

对于在发送onMessageReceived时使用data时不知道如何播放通知默认声音的人，可以将其添加到FirebaseMessagingService扩展名（我的名字是{{1 }}）MyFirebaseMessagingService.java

Answer 1

@Cesar请，您能复制并粘贴发生崩溃的日志猫部分吗？然后我们可以在那里查看确切的错误。

当应用程序处于前台状态时接收通知-（第28页）

1 个答案: