如何将Android短信代码转换为iOS并兼容flutter？

Question

我找到了此代码，该代码允许Flutter自动发送短信。 Flutter send sms with device automatically

import android.Manifest;
import android.content.pm.PackageManager;
import android.os.Build;
import android.os.Bundle;
import android.telephony.SmsManager;
import android.util.Log;
import io.flutter.app.FlutterActivity;
import io.flutter.plugin.common.MethodCall;
import io.flutter.plugin.common.MethodChannel;
import io.flutter.plugins.GeneratedPluginRegistrant;


public class MainActivity extends FlutterActivity {
  private static final String CHANNEL = "sendSms";

  // private MethodChannel.Result callResult;

  @Override
  protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.M) {
      if (checkSelfPermission(
              Manifest.permission.SEND_SMS)
              != PackageManager.PERMISSION_GRANTED) {

        // Should we show an explanation?
        if (shouldShowRequestPermissionRationale(
                Manifest.permission.SEND_SMS)) {

          // Show an explanation to the user *asynchronously* -- don't block
          // this thread waiting for the user's response! After the user
          // sees the explanation, try again to request the permission.

        } else {

          // No explanation needed, we can request the permission.

          requestPermissions(
                  new String[]{Manifest.permission.SEND_SMS},
                  0);

          // MY_PERMISSIONS_REQUEST_SEND_SMS is an
          // app-defined int constant. The callback method gets the
          // result of the request.
        }
      }
    }
    GeneratedPluginRegistrant.registerWith(this);
    new MethodChannel(getFlutterView(), CHANNEL).setMethodCallHandler(
            new MethodChannel.MethodCallHandler() {
              @Override
              public void onMethodCall(MethodCall call, MethodChannel.Result result) {
                if (call.method.equals("send")) {
                  String num = call.argument("phone");
                  String msg = call.argument("msg");
                  sendSMS(num, msg, result);
                } else {
                  result.notImplemented();
                }
              }
            });
  }

  private void sendSMS(String phoneNo, String msg, MethodChannel.Result result) {
    try {
      SmsManager smsManager = SmsManager.getDefault();
      smsManager.sendTextMessage(phoneNo, null, msg, null, null);
      result.success("SMS Sent");
    } catch (Exception ex) {
      ex.printStackTrace();
      result.error("Err", "Sms Not Sent", "");
    }
  }


  @Override
  public void onRequestPermissionsResult(int requestCode,
                                         String permissions[], int[] grantResults) {
    switch (requestCode) {
      case 0: {
        // If request is cancelled, the result arrays are empty.
        if (grantResults.length > 0
                && grantResults[0] == PackageManager.PERMISSION_GRANTED) {

          // permission was granted, yay! Do the
          // contacts-related task you need to do.

        } else {

          // permission denied, boo! Disable the
          // functionality that depends on this permission.
        }
        return;
      }

      // other 'case' lines to check for other
      // permissions this app might request.
    }
  }
}

此代码对我有用。我可以在没有打开本机SMS APP的情况下在Android设备上以短促方式发送SMS：）

但是，我在iOS上搜索了相同的代码，因为Flutter中没有可自动发送SMS的Android软件包和iOS sms软件包。

这是需要在Android和iOS之间架起桥梁的颤动代码。

import 'dart:async';
import 'package:flutter/material.dart';
import 'package:flutter/widgets.dart';
import 'package:flutter/services.dart';

void main() {
  runApp(new MaterialApp(
    title: "Rotation Demo",
    home: new SendSms(),
  ));
}


class SendSms extends StatefulWidget {
  @override
  _SendSmsState createState() => new _SendSmsState();
}

class _SendSmsState extends State<SendSms> {
  static const platform = const MethodChannel('sendSms');
String num="+33XXXXXXXXX";
  Future<Null> sendSms()async {
    print("SendSMS");
    try {
      final String result = await platform.invokeMethod('send',<String,dynamic>{"phone":"$num","msg":"Hello! I'm sent programatically."}); //Replace a 'X' with 10 digit phone number
      print(result);
    } on PlatformException catch (e) {
      print(e.toString());
    }
  }

  Future<Null> sendSms2()async {
    print("SendSMS");
    try {
      final String result = await platform.invokeMethod('send',<String,dynamic>{"phone":"$num","msg":"test baby"}); //Replace a 'X' with 10 digit phone number
      print(result);
    } on PlatformException catch (e) {
      print(e.toString());
    }
  }

  @override
  Widget build(BuildContext context) {
    return new Material(
      child: new Column(
        children: <Widget>[
          new FlatButton(onPressed: () => sendSms(), child: const Text("Send SMS")),
          new FlatButton(onPressed: () => sendSms2(), child: const Text("Send SMS")),
        ],
      )


    );
  }
}

编辑：如果不打开本机SMS，iOS将无法自动发送短信...