Question

下面的方法总是返回一个空数组，因为查询是从MySQL返回数据。

如果我像这样写SELECT * FROM menu
此问题出现在AWS EC2服务器上，并且该方法在我的本地主机上正常工作
此SELECT * FROM menu WHERE type = ? ORDER BY likes DESC查询在添加位置列以更新表格之前运行良好，现在没有人可以使用

我试图从头开始重新创建表

function getMenu($type)
{
    $stmt = $this->con->prepare("SELECT * FROM menu WHERE type = ? ORDER BY likes DESC");
    $stmt->bind_param("s", $type);
    $stmt->execute();
    $stmt->bind_result($id, $dish_name, $dish_disc, $type, $image, $location, $likes, $price);
}
function getMenuByLocation($type, $location){
    $common = 'common';
    $stmt = $this->con->prepare("SELECT * FROM menu WHERE type = ? AND 
       location IN (?, 'common') ORDER BY likes DESC");
    $stmt->bind_result($id, $dish_name, $dish_disc, $type, $image, 
         $location, $likes, $price);
    while ($stmt->fetch()) {
        $temp = array();

        $temp['dId'] = $id;
        $temp['dishName'] = $dish_name;
        $temp['dishDisc'] = $dish_disc;
        $temp['type'] = $type;
        $temp['imageUrl'] = $image;
        $temp['location'] = $location;
        $temp['likes'] = $likes;
        $temp['price'] = $price;

        array_push($dish, $temp);
    }
    return $dish;
}

Answer 1

我认为您的问题与表'menu'上的用户权限有关。检查用户权限

SHOW GRANTS FOR 'user'@'domain';

在连接字符串中将'user'@'domain'更改为您的用户名。

尝试

GRANT ALL ON your_db_name.menu TO 'user'@'domain';

请注意，此查询应由具有足够特权的用户执行。

根据需要参考https://dev.mysql.com/doc/refman/5.5/en/privilege-system.html。

如何解决这个查询

1 个答案: