我正在尝试在Kotlin代码中使用fastjson解析对象。但是当我使用JSON.parseObject时发生了异常,这是详细信息:
我的数据类:
import com.alibaba.fastjson.JSONObject
data class StatesMessage @JvmOverloads constructor(val command: String =
"states", var states: States = States()) {
fun toJsonString(): String {
return JSONObject.toJSONString(this)
}
data class States(var x: Double = 0.0, var y: Double = 0.0)
}
然后我尝试从字符串中获取对象:
val state = JSON.parseObject(s, StatesMessage::class.java)
但是从fastjson抛出异常:
Caused by: com.alibaba.fastjson.JSONException: default constructor not found.
class com.example.demo.StatesMessage
at com.alibaba.fastjson.util.JavaBeanInfo.build(JavaBeanInfo.java:475)
at com.alibaba.fastjson.util.JavaBeanInfo.build(JavaBeanInfo.java:221)
at com.alibaba.fastjson.parser.ParserConfig.createJavaBeanDeserializer(ParserConfig.java:670)
at com.alibaba.fastjson.parser.ParserConfig.getDeserializer(ParserConfig.java:587)
at com.alibaba.fastjson.parser.ParserConfig.getDeserializer(ParserConfig.java:398)
at com.alibaba.fastjson.parser.DefaultJSONParser.parseObject(DefaultJSONParser.java:665)
at com.alibaba.fastjson.JSON.parseObject(JSON.java:365)
at com.alibaba.fastjson.JSON.parseObject(JSON.java:269)
at com.alibaba.fastjson.JSON.parseObject(JSON.java:488)
at com.example.demo.StartupRunner.run(StartupRunner.kt:25)
at org.springframework.boot.SpringApplication.callRunner(SpringApplication.java:813)
... 5 more
答案 0 :(得分:0)
我认为这是一个fastjson(直到1.2.54)错误。 当我改用gson时,就可以了。
/* it will throw exception
val state = JSON.parseObject(s, StatesMessage::class.java)
*/
val state = Gson().fromJson(s, StatesMessage::class.java)
logger.info(state.states.x)
logger.info(state.states.y)