Question

>>> Exception in Tkinter callback
Traceback (most recent call last):
  File "C:\Users\Maximillian\AppData\Local\Programs\Python\Python37-32\lib\tkinter\__init__.py", line 1705, in __call__
    return self.func(*args)
  File "C:\Python-koding\steinsakspapir.py", line 64, in scissors
    botwin += 1
UnboundLocalError: local variable 'botwin' referenced before assignment

-尝试从其余代码中删除botwin和youwin -尝试使用youwin = youwin + 1

    def scissors():
        bot = random.randint(1,3)
       user = 3
       if user == bot:
            printfuver = ("Stalemate, booth players choose scissors")
           printfu = Label(lowerframe, text=printfuver, fg="blue")
            printfu.pack()
        if user == 3 and bot == 1:
            printfuver = ("Rock crushes scissors, bot win! ")
            printfu = Label(lowerframe, text=printfuver, fg="red")
            printfu.pack()
            botwin += 1
        if user == 3 and bot == 2:
            printfuver = ("Scissors cut paper, you win! ")
            printfu = Label(lowerframe, text=printfuver, fg="green")
            printfu.pack()
            youwin += 1

只希望每次运行该功能后，botwin的值就增加1。

预先感谢

Answer 1

除了代码中的缩进错误外，这可能是范围问题。检查并确保您的代码中有botwin = 0或类似内容。如果该代码在函数中或超出全局范围，则将其放在代码的顶部。然后，在引用它的所有函数中，将global botwin放在函数的开头，如here所述。

希望对您有帮助。

如何在Python中向用户定义函数添加计数器？

1 个答案: