Question

我需要修改此代码，以替换数字1和当前小节的编号。所以，第一个每个小节中的数字总是会增加。

代替

（每个数字都单独一行），我现在打印

1 2 3 4 2 2 3 4 3 2 3 4

，依此类推。

beats_per_measure = 4
measures = 5

for measure in range(0, measures):     
    for beat in range(1, beats_per_measure + 1):
        print(beat)

Answer 1

也许您需要以下类似的东西。

beats_per_measure = 4
measures = 5

### loop from 1 to 5 measures ###
# remove +1 to get sequence of 4
# iterations
for measure in range(1, measures+1):

  # print the measure value in a single line
  # first at iteration of outer loop to get
  # the sequence
  print(measure, end = " ")

  ## then loop from 2 to measure
  for beat in range(2, beats_per_measure + 1):
    # print each beat
    print(beat, end = " ")

输出

1 2 3 4 2 2 3 4 3 2 3 4 4 2 3 4 5 2 3 4

Answer 2

您可以通过手动打印当前所在的小节来解决此问题-紧随其后的是剩余节拍：

beats_per_measure = 4
measures = 5

for m in range(measures):  
    # manually print the measure you are in
    print(m+1, end=" ") # do not put a newline after the print statement

    # print the beats 0...bmp-1 == 0,1,2 - output adds 2 to each => 2,3,4
    for beat in range(beats_per_measure - 1):
        print(beat+2, end = " ") # do not put a newline after the print statement

输出：

1 2 3 4 2 2 3 4 3 2 3 4 4 2 3 4 5 2 3 4
*       *       *       *       *

*是手动打印的，其余的由for循环填充

您可以在此处阅读有关单行打印的更多信息：

Doku：https://docs.python.org/3/library/functions.html#print

您还可以创建一个生成器，该生成器自己对小节进行计数（我将用*手动标记小节编号）：

def gimme_measure(beats_per_measure): 
    beats = list(range(2,beats_per_measure+1))

    yield gimme_measure.measure 
    gimme_measure.measure += 1
    yield from beats 

gimme_measure.measure = 1  # defines the starting measure


# print 2*10 measures
for _ in range(10):
    print(*gimme_measure(4), end = " ") # the * decomposes the values from the generator
for _ in range(10): # continues the beat measuring
    print(*gimme_measure(4), end = " ") # the * decomposes the values from the generator

输出：

1 2 3 4 2 2 3 4 3 2 3 4 4 2 3 4 5 2 3 4 6 2 3 4 7 2 3 4 8 2 3 4 9 2 3 4 10 2 3 4 11 2 3 4 12 2 3 4 13 2 3 4 14 2 3 4 15 2 3 4 16 2 3 4 17 2 3 4 18 2 3 4 19 2 3 4 20 2 3 4 
*       *       *       *       *       *       *       *       *       **       **       **       **       **       **       **       **       **       **       **

生成器gimme_measure拥有自己的度量计数器，每次使用生成器生成新度量时，该计数器都会初始化为1，并且如果不将gimme_measure.measure重置为其他数字，它将保持不变每当您打印另一个生成的度量时，都向上计数。

您甚至可以将不同的bpm链接在一起：

# piece with 2 measures of 4 beats, 2 measures of 8 beats, 2 measures of 3 beats
for _ in range(2):
    print(*gimme_measure(4), end = " ")  

for _ in range(2): # continues the beat measuring
    print(*gimme_measure(8), end = " ")  

for _ in range(2): # continues the beat measuring
    print(*gimme_measure(3), end = " ")

输出：

1 2 3 4 2 2 3 4 3 2 3 4 5 6 7 8 4 2 3 4 5 6 7 8 5 2 3 6 2 3
*       *       *               *               *     *

Answer 3

如果您使用的是python 3，这是答案（已测试）：

beats_per_measure = 4
measures = 5

for measure in range(1, measures+1):
    print(measure, end = ' ')
    for beat in range(2, beats_per_measure + 1):
        print(beat, end = ' ')

或者，如果您使用的是python 2，请使用此（已测试）：

beats_per_measure = 4
measures = 5

for measure in range(1, measures+1):
    print measure,  
    for beat in range(1, beats_per_measure + 1):
        print beat,

此处有更多信息：https://www.quora.com/How-do-I-print-something-on-the-same-line-in-Python

如何使代码打印1 2 3 4 2 2 3 4 3 2 3 4，依此类推？使用For循环

3 个答案: