如何在C ++中构造动态2D数组？

Question

我正在尝试通过审核Coursera课程来完善我的C ++，但不确定如何使数组动态变化。

我首先声明一个名为HexTiles的类：

class HexTile {
public:
    HexTile() :x(0), y(0), c(Color::NONE) {} //Default constructor for (0,0), blank tile
    HexTile(int x_input, int y_input, Color c_input = Color::NONE) : x(x_input), y(y_input), c(c_input) { 
             /* Make sure the input coordinates are in range */
        assert(x >= 0 && x < x_max);
        assert(y >= 0 && y < y_max);
    }
    ~HexTile() { delete this; } //Destructor
    friend ostream& operator << (ostream& out, HexTile& hex);
    void ChangeColor(Color c_input) { c = c_input; }
    Color GetColor(void) { return c; }
private:
    int x, y; //Coordinates
    Color c; //Shows which player owns the tile
};

这里没有什么特别令人惊讶的。

然后我声明一个HexTables类，该类将一堆hextiles映射到一个数组：

class HexTable {
public:
    HexTable(); //Default constructor

    HexTable(int x_width, int y_width); //Constructor for custom dimensions

    ~HexTable() { 
        delete[] hex_array;
        delete this; 
    } //Destructor

    friend ostream& operator<<(ostream& out, HexTable& table);

    void SetTableSize(int i) { x_width = i; y_width = i; }

    void PlayTile(int x, int y, Color c) { hex_array[x][y]->ChangeColor(c); }

    /* Make sure x and y are both within range */
    bool isLegal(int x, int y) { return (x >= 0 && x < x_max) && (y >= 0 && y < y_max && hex_array[x][y]->GetColor() == Color::NONE); }
private:
    int x_width, y_width;
    HexTile* hex_array[x_max][y_max];
};

HexTable构造函数创建一堆HexTiles，并将它们放置在数组中。

HexTable::HexTable(){
    x_width = x_max;
    y_width = y_max;
    /* Nested for loop to initialize all hex tiles */
    for (int i=0; i<x_width; i++) {
        for (int j = 0; j < y_width; j++) {
            HexTile* p_hex = new HexTile(i,j); //Declare a new hextile at coordinates (i,j) and assign Color BLANK
            hex_array[i][j] = p_hex; //Assign hex_array with p_hex pointer
        }
    }
}

它当前有效，但是我不喜欢将大小固定为[x_max] x [y_max]，它们是固定的全局常量。我想使表大小动态化。我想到了把戏         HexTile** hex_array = new HexTile*[x_width]; for(int i=0; i<x_width;i++) hex_array[i] = new HexTile[y_width]; 但是会占用我通过数组查找[x] [y]查找hex_array的能力。任何专家都知道该怎么办？谢谢。