Question

有没有一种方法可以在python中编写“ for”循环和“ If Else”，从而搜索一个句子并找到以相同字母开头和结尾的单词数量？我试过写类似的东西：

sentence = "Mom knock the door"

list = sentence.split()
for word in sentence:
    if ...

Answer 1

只需将字符串开头的字符与字符串结尾的字符进行比较，如下所示：

if word[0] == word[-1]:

如果不区分大小写，请首先通过调用以下单词来降低该单词：

word = word.lower()

Answer 2

words_list = sentence.split()
new_words_list = []
for word in words_list:
    if word[0] == word[-1]:
        new_words_list.append(word)

print('Number of words that starts and ends with same letter - {}'.format(len(new_words_list)))

您也可以通过列表理解来做到这一点：

new_words_list = [word for word in words_list if word[0] == word[-1]]

如果不想区分大小写，请使用word[0].lower()和word[-1].lower()而不是word[0]和word[-1]

Answer 3

上面的答案都很聪明，我更喜欢以函数式编程的方式来处理它，就像这样：

sentence = "Mom knock the door"


def is_same_letter_at_begin_end(word):
    return word and word[0].lower() == word[-1].lower()


target_words = list(filter(is_same_letter_at_begin_end, sentence.split()))
print(target_words)
print(len(target_words))

Answer 4

list = sentence.split(" ")
count = 0
for word in list:
    lc_word = word.lower()
    if lc_word[0] == lc_word[-1]:
        count +=1

Answer 5

lst = sentence.split()
num_words = 0
for i in lst:
    low = i.lower()
    if low[0] == low[len(low)-1]:
        num_words += 1
return num_words

Answer 6

list或set理解不区分大小写：

sentence = "Mom knock the door, mom"
all_words_count = len([ word for word in sentence.split() if word[0].lower() == word[-1].lower() ])
uniq_words_count = len({word.lower() for word in sentence.split() if word[0].lower() == word[-1].lower()})

print(all_words_count) #=> 3
print(uniq_words_count) #=> 2

如何在以相同字母开头和结尾的句子中找到单词？

6 个答案: