在我的Spring Boot项目中,我有以下@ManyToOne
关系字段,它引用与父对象相同的@Entity
。
@Entity
@Table(name="workspace")
public class Workspace extends AbstractEntity {
@NaturalId
@Column(nullable=false, unique=true)
private String code;
@ManyToOne(fetch=FetchType.LAZY, optional=true)
@LazyToOne(LazyToOneOption.NO_PROXY)
@JoinColumn(name="default_workspace", referencedColumnName="code")
private Workspace parent;
private String name;
private String shortName;
}
延迟加载行为正在按预期方式工作。但是,每次我在此@Repository.save()
上调用@Entity
时,default_workspace
字段都会设置为NULL
。
更新:在注释中包括一些要求的配置
要使用Hibernate启用延迟加载,我只是在hibernate-enhance-maven-plugin
中加入了pom.xml
插件。
<?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>
<groupId>com.ft</groupId>
<artifactId>com.ft.admin</artifactId>
<version>0.0.1-SNAPSHOT</version>
<packaging>jar</packaging>
<parent>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-parent</artifactId>
<version>2.1.1.RELEASE</version>
<relativePath/> <!-- lookup parent from repository -->
</parent>
<properties>
<java.version>1.8</java.version>
<project.build.sourceEncoding>UTF-8</project.build.sourceEncoding>
</properties>
<dependencies>
<dependency>
<groupId>com.ft</groupId>
<artifactId>com.ft.common</artifactId>
<version>${project.version}</version>
</dependency>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-devtools</artifactId>
<scope>runtime</scope>
</dependency>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-test</artifactId>
<scope>test</scope>
</dependency>
</dependencies>
<build>
<plugins>
<plugin>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-maven-plugin</artifactId>
</plugin>
<plugin>
<groupId>org.hibernate.orm.tooling</groupId>
<artifactId>hibernate-enhance-maven-plugin</artifactId>
<version>${hibernate.version}</version>
<executions>
<execution>
<configuration>
<failOnError>true</failOnError>
<enableLazyInitialization>true</enableLazyInitialization>
</configuration>
<goals>
<goal>enhance</goal>
</goals>
</execution>
</executions>
</plugin>
</plugins>
</build>
</project>
要在我的Workspace
上执行CRUD过程,请使用以下@Repository
。
@Repository
public interface WorkspaceRepo extends CrudRepository<Workspace, Integer> {
Optional<Workspace> findByCode(String workspaceCode);
}
默认情况下,在Spring Boot中,事务的边界保留在对@Repository
的每次调用中。因此,为了能够访问我的延迟加载字段而不会遇到LazyInitializationException: no Session
,我在@Transactional
上添加了@Service
来扩展事务边界,如下所示。
@Service
@Transactional
public class AppAdminService {
@Autowired
private WorkspaceRepo workspaceRepo;
public void updatePsyWorkspace() {
Workspace childWorkspace = workspaceRepo.findByCode("PSY").get();
childWorkspace.setShortName("PSY SHORT");
workspaceRepo.save(childWorkspace);
}
}
当我执行WorkspaceRepo.findByCode(code)
时,我会得到一个带有有效非空parent
的子记录。但是,每当我执行WorkspaceRepo.save(childWorkspace)
时,即使我只更新了parent
,NULL
也会被设置为default_workspace
,并且NULL
列也将在数据库中变为ShortName
。 String
字段,如上例所示。
更新:临时解决方案
作为一个临时解决方案,我必须为default_workspace
列添加一个普通的parent
字段,并从Hibernate操作中排除@Entity
@Table(name="workspace")
@Getter @Setter
public class Workspace extends AbstractEntity {
...
@ManyToOne(fetch=FetchType.LAZY, optional=true)
@LazyToOne(LazyToOneOption.NO_PROXY)
@JoinColumn(
name="default_workspace",
referencedColumnName="code",
insertable=false,
updatable=false)
private Workspace parent;
@Getter(AccessLevel.NONE)
@Setter(AccessLevel.NONE)
@Column(name="default_workspace")
private String defaultWorkspace;
public void setParent(Workspace parent) {
this.parent = parent;
this.defaultWorkspace = (parent != null) ? parent.getCode() : null;
}
...
}
字段,如下所示。
AccessLevel.NONE
通过使用parent
,我将该字段完全隐藏在外部世界之外。任何用于更新defaultWorkspace
字段的调用都会另外更新// declaring a comparator method
$scope.filterBy = function(actual, expected) {
return _.contains(expected, actual); // uses underscore library contains method
};
var employees = [{name: 'a'}, {name: 'b'}, {name: 'c'}, {name: 'd'}];
// filter employees with name matching with either 'a' or 'c'
var filteredEmployees = $filter('filter')(employees, {name: ['a','c']}, $scope.filterBy);
字段。即使此解决方案有效,但对我来说还是不合适。
如果您能向我展示实现同一目标的更好方法,我将不胜感激。