Question

我试图使用Javascript选择名称值包含字符串“ visitors”的所有元素。在这种情况下，我无法添加课程。

<select name="visitors10">
   <option class="disableDuration4" value="5">5</option>
   <option class="disableDuration5" value="6">6</option>
   <option class="disableDuration6" value="7">7</option>
</select>
<select name="visitors11">
   <option class="disableDuration4" value="5">5</option>
   <option class="disableDuration5" value="6">6</option>
   <option class="disableDuration6" value="7">7</option>
</select>
<select name="visitors12">
   <option class="disableDuration4" value="5">5</option>
   <option class="disableDuration5" value="6">6</option>
   <option class="disableDuration6" value="7">7</option>
</select>

Answer 1

尝试一下

document.querySelectorAll("select[name^=visitors]")

Answer 2

您可以使用querySelectorAll

这样操作

<select name="visitors10">
   <option class="disableDuration4" value="5">5</option>
   <option class="disableDuration5" value="6">6</option>
   <option class="disableDuration6" value="7">7</option>
</select>
<select name="visitors11">
   <option class="disableDuration4" value="5">5</option>
   <option class="disableDuration5" value="6">6</option>
   <option class="disableDuration6" value="7">7</option>
</select>
<select name="visitors12">
   <option class="disableDuration4" value="5">5</option>
   <option class="disableDuration5" value="6">6</option>
   <option class="disableDuration6" value="7">7</option>
</select>
<select name="xyz"></select>
<select name="visitorsxyz"></select>

bc

使用Javascript按名称获取包含字符串一部分的元素

2 个答案: