Question

我正在尝试在游戏中实现滑动控件，并希望仅在屏幕左侧检测到滑动，并保持游戏的其他控制机制不变。

我正在使用此SwipeManager：

public enum Swipes { None, Up, Down, Left, TopLeft, BottomLeft, Right, TopRight,  BottomRight};

public class SwipeManager : MonoBehaviour
{
    public float minSwipeLength = 200f;

    private Vector2 fingerStart;
    private Vector2 fingerEnd;

    public static Swipes direction;
    public static float angle;
    public static Vector2 strength;

    public static bool debugMode = false;

    void Update ()
    {
        SwipeDetection();
    }

    public void SwipeDetection ()
    {
        if (Input.GetMouseButtonDown(0)) {
            fingerStart = Input.mousePosition;
            fingerEnd  = Input.mousePosition;
        }

        if(Input.GetMouseButton(0)) {
            fingerEnd = Input.mousePosition;

            strength = new Vector2 (fingerEnd.x - fingerStart.x, fingerEnd.y - fingerStart.y);

            // Make sure it was a legit swipe, not a tap
            if (strength.magnitude < minSwipeLength) {
                direction = Swipes.None;
                return;
            }

            angle = (Mathf.Atan2(strength.y, strength.x) / (Mathf.PI));
            if (debugMode) Debug.Log(angle);
            // Swipe up
            if (angle>0.375f && angle<0.625f) {
                direction = Swipes.Up;
                if (debugMode) Debug.Log ("Up");
                // Swipe down
            } else if (angle<-0.375f && angle>-0.625f) {
                direction = Swipes.Down;
                if (debugMode) Debug.Log ("Down");
                // Swipe left
            } else if (angle<-0.875f || angle>0.875f) {
                direction = Swipes.Left;
                if (debugMode) Debug.Log ("Left");
                // Swipe right
            } else if (angle>-0.125f && angle<0.125f) {
                direction = Swipes.Right;
                if (debugMode) Debug.Log ("Right");
            }
            else if(angle>0.125f && angle<0.375f){
                direction = Swipes.TopRight;
                if (debugMode) Debug.Log ("top right");
            }
            else if(angle>0.625f && angle<0.875f){
                direction = Swipes.TopLeft;
                if (debugMode) Debug.Log ("top left");
            }
            else if(angle<-0.125f && angle>-0.375f){
                direction = Swipes.BottomRight;
                if (debugMode) Debug.Log ("bottom right");
            }
            else if(angle<-0.625f && angle>-0.875f){
                direction = Swipes.BottomLeft;
                if (debugMode) Debug.Log ("bottom left");
            }
        }

        if(Input.GetMouseButtonUp(0)) {
            direction = Swipes.None;  
        }
    }
}

我想在屏幕左侧创建一个面板，并且希望仅在面板上检测到滑动，在该面板外部单击的任何位置（即屏幕右侧）都不应被视为滑动，而是目标（现在已设置）

谢谢

Answer 1

一种解决方案是，当鼠标指针位于面板之外时跳过SwipeDetection。因此，如果您可以获得对面板RectTransform的引用，则只需在调用SwipeDetection之前检查鼠标指针是否位于其中。

要考虑到用户按下面板之外然后进入面板的可能性，可以将fingerStart = Input.mousePosition;分配给鼠标不在矩形区域之外的人。

总的来说，这看起来像：

public RectTransform rectTransform; // panel RectTransform assigned to this variable

...

void Update ()
{
    Vector2 mousePosition = Input.mousePosition;

    if (RectTransformUtility.RectangleContainsScreenPoint(rectTransform, mousePosition))
    {
        SwipeDetection();
    }
    else 
    {
        fingerStart = Input.mousePosition;
        direction = Swipes.None;
    }
}

有什么方法可以将触摸输入限制为Unity3D中的面板？

1 个答案: