我有两个熊猫数据框,第一个包含城市及其坐标,另一个包含机场及其坐标(以下示例)。我想计算一个给定城市在一定距离(大地)内有多少个机场,并将其作为城市数据框中的一列。这是数据框的标题(机场然后是城市):
| Name | IATA | City | Latitude | Longitude |
|--------------------------------------------------|-------------|--------------|--------------|-------------|
| Hartsfield Jackson Atlanta International Airport | ATL | Atlanta | 33.636700 | -84.428101 |
| Los Angeles International Airport | LAX | Los Angeles | 33.942501 | -118.407997 |
| Chicago O'Hare International Airport | ORD | Chicago | 41.978600 | -87.904800 |
| city | city_lat | city_long | airports_80miles |
|----------------------------------------|------------------|-------------------|--------------------------|
| Akron, OH Metro Area | 41.146639 | -81.350110 | 0 |
| Albany, OR Metro Area | 44.488898 | -122.537208 | 0 |
| Albany-Schenectady-Troy, NY Metro Area | 42.787920 | -73.942348 | 0 |
这是要使用的直接函数:
def distance(origin, destination):
lat1, lon1 = origin
lat2, lon2 = destination
radius = 6371 # km
lat1 = math.radians(lat1)
lat2 = math.radians(lat2)
lon1 = math.radians(lon1)
lon2 = math.radians(lon2)
dlat = (lat2-lat1)
dlon = (lon2-lon1)
a = math.sin(dlat/2) * math.sin(dlat/2) + math.cos(lat1) \
* math.cos(lat2) * math.sin(dlon/2) * math.sin(dlon/2)
c = 2 * math.atan2(math.sqrt(a), math.sqrt(1-a))
d = radius * c
return d*0.62
如何在每个城市上应用此距离函数,遍历机场及其坐标的数据框?
谢谢!
答案 0 :(得分:0)
两次使用apply
函数:
假设机场数据框为df1
,城市数据框为df2
,阈值距离为80。
threshold_distance = 80.0
df2["Airports_within_threshold"] = df2.apply(lambda x:
df1.apply(lambda y:
distance((x["city_lat"], x["city_long"]),
(y["Latitude"],y["Longitude"]))
< threshold_distance, axis = 1),
axis = 1).sum(axis = 1)