我正在尝试创建一个视频,用于加载目录中的视频,并依赖于用户ID等。
要做到这一点,我正在使用PHP。但是,我不能让php在actionscript中转换为xml:
这是php代码:
$query = "SELECT * FROM video_files ORDER BY video_id DESC";
$resultID = mysql_query($query) or die("Data not found.");
$xml_output = "<?xml version=\"1.0\" encoding=\"utf-8\"?>\n";
$xml_output .= "<PLAYLIST VIDEO_X=\"0\" VIDEO_Y=\"0\" >\n";
for($x = 0 ; $x < mysql_num_rows($resultID) ; $x++){
$row = mysql_fetch_assoc($resultID);
$xml_output .= "<VIDEO TITLE=\"".$row['title']."\" THUMB=\"\" URL=\"".$row['path']."\"/>\n";
}
$xml_output .= "</PLAYLIST>";
echo $xml_output;
这是动作脚本:
import fl.video.*;
var thumb_width:Number;
var thumb_height:Number;
var thumbs_x:Number;
var thumbs_y:Number;
var video_x:Number;
var video_y:Number;
var my_videos:XMLList;
var my_total:Number;
var main_container:Sprite;
var thumbs:Sprite;
var titles:Sprite;
var my_player:FLVPlayback;
var myXMLLoader:URLLoader = new URLLoader();
myXMLLoader.load (new URLRequest("playlist.php"));
myXMLLoader.addEventListener (Event.COMPLETE, processXML);
function processXML (e:Event):void {
var myXML:XML = new XML(e.target.data);
thumb_width = myXML.@THUMB_WIDTH;
thumb_height = myXML.@THUMB_HEIGHT;
thumbs_x = myXML.@THUMBS_X;
thumbs_y = myXML.@THUMBS_Y;
video_x = myXML.@VIDEO_X;
video_y = myXML.@VIDEO_Y;
my_videos = myXML.VIDEO;
my_total = my_videos.length();
makeContainers ();
callThumbs ();
makePlayer ();
}
function makeContainers ():void {
main_container = new Sprite();
addChild (main_container);
thumbs = new Sprite();
thumbs.addEventListener (MouseEvent.CLICK, playVideo);
thumbs.addEventListener (MouseEvent.MOUSE_OVER, onOver);
thumbs.addEventListener (MouseEvent.MOUSE_OUT, onOut);
thumbs.x = thumbs_x;
thumbs.y = thumbs_y;
thumbs.buttonMode = true;
main_container.addChild (thumbs);
titles = new Sprite();
titles.x = thumbs_x;
titles.y = thumbs_y;
main_container.addChild (titles);
}
function callThumbs ():void {
for (var i:Number = 0; i < my_total; i++) {
var thumb_url = my_videos[i].@THUMB;
var thumb_loader = new Loader();
thumb_loader.name = i;
thumb_loader.load (new URLRequest(thumb_url));
thumb_loader.contentLoaderInfo.addEventListener (Event.COMPLETE, thumbLoaded);
thumb_loader.y = (thumb_height+10)*i;
var thumb_title = my_videos[i].@TITLE;
var title_txt:TextField = new TextField();
title_txt.text = thumb_title;
title_txt.y = thumb_loader.y;
title_txt.x = thumb_width + 10;
title_txt.width = thumb_width;
title_txt.height = thumb_height;
title_txt.wordWrap = true;
titles.addChild (title_txt);
}
}
function thumbLoaded (e:Event):void {
var my_thumb:Loader = Loader(e.target.loader);
thumbs.addChild (my_thumb);
}
function makePlayer ():void {
my_player = new FLVPlayback();
my_player.skin ="videos/videoskin.swf";
my_player.skinBackgroundColor = 0xAEBEFB;
my_player.skinBackgroundAlpha = 0.9;
my_player.x = video_x;
my_player.y = video_y;
my_player.width = 500;
my_player.height = 400;
main_container.addChild (my_player);
my_player.source = my_videos[0].@URL;
}
function playVideo (e:MouseEvent):void {
var video_url = my_videos[e.target.name].@URL;
my_player.source = video_url;
}
function onOver (e:MouseEvent):void {
var my_thumb:Loader = Loader(e.target);
my_thumb.alpha = 0.5;
}
function onOut (e:MouseEvent):void {
var my_thumb:Loader = Loader (e.target);
my_thumb.alpha = 1;
}
谁知道我哪里出错了?它适用于普通的xml文件而不是php
答案 0 :(得分:0)
PHP中XML输出的格式错误。每个标签都必须关闭。
你有:
<?xml version="1.0" encoding="utf-8"?>
<PLAYLIST VIDEO_X="0" VIDEO_Y="0">
<VIDEO TITLE="videotitle" THUMB="thumbnail" URL="URL" />
</PLAYLIST>
您需要关闭视频标记。所以输出应该如下所示:
<?xml version="1.0" encoding="utf-8"?>
<PLAYLIST VIDEO_X="0" VIDEO_Y="0">
<VIDEO TITLE="videotitle" THUMB="thumbnail" URL="URL"></VIDEO>
</PLAYLIST>
您还应该为PHP脚本设置内容类型。
header('Content-type: text/xml');
我无法访问我的笔记本电脑来彻底测试您的代码,但这是我第一眼看到您的代码后的答案。