Question

我正在尝试使用python创建一个hang子手游戏。我知道还有很多事情要做，但我想弄清楚游戏的主要组成部分，即如何将用户输入的字符串（一个字母）与三个随机选择的单词之一中的字母进行比较。

import random

print("Welcome to hangman,guess the five letter word")
words =["china", "ducks", "glass"]
correct_word = (random.choice(words))
guess = input(str("Enter your guess:"))
guess_left = 10
guess_subtract = 1
if guess == "":
    guess_left = guess_left - guess_subtract
    print("you have" + guess_left + "guesses left")

Answer 1

我认为您需要一个骨架，然后花一些时间来改善游戏。

import random

print "Welcome to hangman, guess the five letter word"

words = ["china", "ducks", "glass"]
correct_word = (random.choice(words))

trials = 10

for trial in range(trials):
    guess = str(raw_input("Enter character: "))

    if (len(guess) > 1):
        print "You are not allowed to enter more than one character at time"
        continue

    if guess in correct_word:
        print "Well done! '" + guess + "' is in the list!"
    else:
        print "Sorry " + guess + " does not included..."

您的下一步可能会打印出类似c_i__的内容以及剩余的试用次数。玩得开心：）

完成实施后，请花一些时间并使用函数重新实施。

Answer 2

您可以做的是将字符串视为数组/列表。因此，如果您使用循环：

x = ""#let's assume this is the users input
for i in range(len(y)): #y is the string your checking against
    if x == y[i]:

从这里开始，我想的是，如果它们相等，则会将该字母添加到字符串中

让我们说字符串是“今天很有趣”，然后会有一个像这样的数组，[“ ”。“ ”，依此类推，但是您必须找到一种将空间因素分解的方法和撇号。因此，如果字母==代表字符串的那一部分

#this is a continuation of the code, so under if
thearray[theposition] == the letter

但是，在查看代码时，您的游戏与常规代码有所不同，因此，也请考虑使用一会儿外观

gamewon = False
number of trials = 10

while gamewon == False and number of trials > 0:
    #the whole checking process 
    if x == guess:
       gamewon == True
       print ........# this is if your doing word for word else use 
       the code above
     else:
         number  of trials = number of trials - 1

我想就是这样，我到处都知道，但是您可以随时寻求帮助，我会解释一下，而且我指的是您认为可以解决的代码问题

Answer 3

首先，您应该使用public void setMainView(View mainView) { this.mainView = mainView; setupView(); }接受a和A。您必须在字符串中搜索猜到的字符并找到位置。

guess = guess.lower()

了解for循环的另一种方法是：

guess = guess.lower()

# Find the position(s) of the character guessed
pos = [idx for idx,ch in enumerate(correct_word) if ch == guess]

if pos:
    print('Letter Found')

guess_left -= 1

如何将用户输入的字符串与列表中单词的字符（单个字母）进行比较？

3 个答案: