Question

我试图将代码从PyQt4移植到PyQt5，但不理解为什么以下内容不起作用。未调用该插槽。我看到一堆of子，没有to。我想念什么？

from PyQt5 import QtCore
import time

# expect to see ticks & tocks
class Alarm(QtCore.QThread, QtCore.QObject):
    signal = QtCore.pyqtSignal()

    def __init__(self, parent=None):
        super(Alarm, self).__init__(parent)
        self.signal.connect(self.eventp)
        self.start()

    def run(self):
        while True:
            print('tick')
            self.signal.emit()
            time.sleep(1)

    @QtCore.pyqtSlot()
    def eventp(self):
        print('Tock')

# main
alarm = Alarm()
time.sleep(6)  # wait for countdown, then terminate

Answer 1

第一个QThread已经从QObject继承，因此没有必要将其用作接口。另一方面，QThread必须存在于事件循环中，因为这允许信号的传输，例如，在您的情况下，您要用time.sleep（6）阻塞事件循环，而不是如果您想在之后完成循环6秒使用QTimer：

import time
from PyQt5 import QtCore
# expect to see ticks & tocks
class Alarm(QtCore.QThread):
    signal = QtCore.pyqtSignal()

    def __init__(self, parent=None):
        super(Alarm, self).__init__(parent)
        self.signal.connect(self.eventp)
        self.start()

    def run(self):
        while True:
            print('tick')
            self.signal.emit()
            time.sleep(1)

    @QtCore.pyqtSlot()
    def eventp(self):
        print('Tock')

if __name__ == '__main__':
    import sys
    app = QtCore.QCoreApplication(sys.argv)
    alarm = Alarm()
    QtCore.QTimer.singleShot(6*1000, QtCore.QCoreApplication.quit)
    sys.exit(app.exec_())

PyQt5：如何连接（）和发出（）

1 个答案: