Question

我有这个字符串：

[{"type":"date","label":"Champ Date de ","className":"form-control","name":"date-1545926599900"}]

我需要从标签中删除最后一个空格，实际值为“ Champ Date de”，我需要将其转换为“ Champ Date de”。

这是我的实际代码：

        $form = str_replace('\n','',$request->getParameter('data'));
        $form = str_replace('\t','',$form);
        $form = str_replace('&nbsp;','',$form);
        $form = str_replace('<br>','',$form);
        var_dump($form); die;

问题来自
：str_replace('<br>','',$form);

使用 的

我没有问题，函数str_replace不会添加空格。但是使用<br>在str_replace上添加一个空格，我确实需要在该值的末尾保留任何空格。希望有人可以帮忙。

我可以有多个数组：

'[{"type":"date","label":"Champ Date de ","className":"form-control","name":"date-1545929424866"},{"type":"checkbox-group","label":"You like it ? ","name":"checkbox-group-1545929428281","values":[{"label":"Option 1","value":"1","selected":true}]}]'

Answer 1

使用array_map('trim',$array);的非正则表达式方式如何？

<?php
$json = '[{"type":"date","label":"Champ Date de ","className":"form-control","name":"date-1545926599900"}]';
$array = json_decode($json,1)[0];
$array= array_map('trim',$array);
echo json_encode([$array]);
?>

输出：

[{"type":"date","label":"Champ Date de","className":"form-control","name":"date-1545926599900"}]

演示： https://3v4l.org/qJ9K1

编辑：根据OP的评论

<?php
$json = '[{"type":"date","label":"Champ Date de ","className":"form-control","name":"date-1545929424866"},{"type":"checkbox-group","label":"You like it ? ","name":"checkbox-group-1545929428281","values":[{"label":"Option 1","value":"1","selected":true}]}]';
$array = json_decode($json,1);
$expected = [];
foreach($array as $k=>$v){
    foreach($v as $key=>$value){
        if($key == 'label' && !is_array($value)){
          $expected[$k][$key]= trim($value); 
       }else{
          $expected[$k][$key]= $value; 
       }
    }
}

echo json_encode($expected);
?>

演示： https://3v4l.org/NRlsR

Answer 2

您可以使用正则表达式来实现无循环运行解决方法如下：

$string = '[{"type":"date","label":"Champ Date de ","className":"form-control","name":"date-1545929424866"},{"type":"checkbox-group","label":"You like it ? ","name":"checkbox-group-1545929428281","values":[{"label":"Option 1","value":"1","selected":true}]}]';
$pattern = '/("label":"([\w\s])+)/m';
echo preg_replace_callback($pattern, function($match) {return trim($match[0]);}, $string);

我已经为结果做了回声。您只需要将其分配给变量即可。

php替换标签中的最后一个空格

2 个答案: