Question

此代码有问题，我无法解决。我是Python的初学者

对于菜单3，我想获取每个员工的薪水并计算他的收入，但是代码没有进展。

对于菜单4，我想显示允许员工工作的天数

尽管尝试了一切，我还是无法运行它。你能帮助我吗？

menu = 0
while menu != 6:
menu = int(input("1. Enter Data: "))
if menu == 1:
 fin = "data.txt"
 fout = open(fin, 'w')
 info = ""
 no = 0
 while info != "no":
    info = raw_input("Veri girmek istiyor musunuz? (yes/no)")
    if info != "no" and info == "yes":
        try:
            no = no + 1
            weekdays1 = int(input("09:00-17:00"))
            weekdays2 = int(input("17:00-09:00"))
            weekend1 = int(input("09:00-17:00"))
            weekend2 = int(input("17:00-09:00"))
            freeday = int(input("bu eleman haftada kac gun izinli"))

            totalweekdayshour = (weekdays1 + weekdays2) * 5
            totalweekendhour = (weekend1 + weekend2) * 2

            totalhour = totalweekdayshour + totalweekendhour

            n = int(input("cash for hour"))

            m1 = (weekdays1 * 5) * n
            m2 = (weekdays2 * 5) * (1.5 * n)
            m3 = (weekend1 * 2) * (2 * n)
            m4 = (weekend2 * 2) * (2.5 * n)

            totalsalary = m1 + m2 + m3 + m4

            if weekdays1 >= 9 :
               if weekdays2 >= 9 :
                if weekend1 >= 9 :
                    if weekend2 >= 9 :

                     print ("Hatali calisma saati girisi")

        except:
            print("Oops! Enter a number.")


 fout.write("%s, %s, %s, %s, %s, %s, %s, %s, %s, %s \n" % (
    no, weekdays1, weekdays2, weekend1, weekend2, totalweekdayshour,
 totalweekendhour, totalhour, totalsalary,
    freeday))
 fout.close()

#all work hours for each worker

elif menu == 2:
print "2. Selection"
fin = open("data.txt", "r")
for line in fin:
    mylist = list(line.split(","))
    no = mylist[0]
    totalweekdayshour = mylist[5]
    totalweekendhour = mylist[6]
    totalhour = mylist[7]
    print 'No : ', no
    print 'Total hour : ', totalhour
    print 'Hafta ici calısma saatleri: ', totalweekdayshour
    print 'Hafta sonu calısma saatleri: ', totalweekendhour
    print ""
fin.close()

#collecting the salary of each employee and calculating the revenue doesn't 
work
elif menu == 3:
fin = open("data.txt", "r")
totalexpence = []
i = 0
a1 = 0
for line in fin:
    totalexpence.append(line.split(","))
    a1 = a1 + float(totalexpence[i][8])
    i = i + 1
fin.close
print "4.selection"
print ("Total expence:", a1)
print ""
#shows how many days the employees are allowed (doesn't work)

elif menu == 4:
fin = open("data.txt","r")
i=0
n=0
freeday=fin.read()[i][9]
i=i+1

print freeday

#doesn't work
#45h law

elif menu ==5 :
fin = open("data.txt","r")
for line in fin:
        totalweekdayshour= [5]
        totalweekendhour= [6]
if totalweekdayshour + totalweekendhour >= 45 :


      print ("employees should not work more than 45 hours per week.")

else:
        print ("working hours approved")


fin.close()

Answer 1

Python语法基于缩进，例如C，您可以在其中使用{}将代码分组在一起。

Python代码（必须在缩进位置）：

if my_condition:
    foo('bar')
elif other_condition:
    baz()
else:
    print 'no condition met'

C ++（请注意，缩进可以是不规则的，而无需任何功能更改）：

if (my_condition) {
foo("bar");
} else if (other_condition) {
        baz();
} else std::cout << "no condition met" << std::endl;

其含义是缩进会改变行为！每次缩进将缩进的代码“属于”到最后一条未缩进的行（以“：”结尾）时，无论是if语句，while循环还是其他语句。请参见下面的示例：

if my_condition:
   print 'this line belongs to the if'
print 'this line does not'

因此，第一个建议是清理缩进并考虑它将如何影响代码。

也：

在elif菜单=='4'上，您已经复制了该行。
您导入了我不想要的“ fin”，因为您没有使用该模块。
您已经忘记了close之类的函数上的括号（（））。
您使用的是“ input”而不是“ raw_input”（假设您使用的是python 2而不是3）
您有时会将print当作函数，而有时将其视为语句。
“ freeday = fin.read [i] [9]”应为“ freeday = fin.read（）[i] [9]”

使用python的员工数据库存在严重问题

1 个答案: