Question

#include <stdio.h>
// this creates the structure  
struct time
{
    int hour;
    int minute;
    int second;
};

//function that calculates the time

struct time timeUpdate(struct time now)
{

    now.second = now.second + 1;

    if (now.second == 60)
    {
        now.second = 0;
        now.minute = now.minute + 1;

        if (now.minute == 60)
        {
            now.minute = 0;
            now.hour = now.hour + 1;
        }
            if (now.hour = 60)
            {
                now.hour = 0;
            }
    }
    return now;
}

//user input and output   
int main(void)
{
    struct time currentTime, nextTime;

    printf("Please enter the current time: ");
    scanf("%i:%i:%i\n", &currentTime.hour, &currentTime.minute, &currentTime.second);

    nextTime = timeUpdate(currentTime);

    printf("%.2i:%.2i:%.2i\n", nextTime.hour, nextTime.minute, nextTime.second);

    return 0;
}

Answer 1

假设您的输入有效（0 <=小时<= 23 && 0 <=分钟<= 59 && 0 <=秒<= 59），这是我的观察结果：

在timeUpdate中，您说now.hour =60。您必须检查now.hour是否等于24 （if (now.hour == 24)）这是您的功能应为的方式：

now.second = now.second + 1;

if (now.second == 60)
{
    now.second = 0;
    now.minute = now.minute + 1;

    if (now.minute == 60)
    {
        now.minute = 0;
        now.hour = now.hour + 1;

        if (now.hour == 24)
        {
            now.hour = 0;
        }
    }
}

return now;

我从scanf删除了'\ n'，因为我很困惑为什么程序不显示结果（我必须写一个字符并按Enter键才能看到结果）。现在，该行看起来像这样scanf("%i:%i:%i", &currentTime.hour, &currentTime.minute, &currentTime.second);

如何获得正确的时间

1 个答案: