我正在尝试修复一个小错误。我有一个UISegmentedControl
,如果我在按下某个段的同时向后导航(不松开要从屏幕上选择该段的手指),它将始终显示用户交互:
我尝试取消选择viewWillDisappear
上的句段,但没有任何区别。关于如何重置UISegmentedControl
的状态的任何想法?
override func viewWillDisappear(_ animated: Bool) {
super.viewWillDisappear(animated)
fixedPositionSegmentControl.selectedSegmentIndex = UISegmentedControl.noSegment
fixedPositionSegmentControl.selectedSegmentIndex = 0
}
答案 0 :(得分:1)
问题在于,在这种特定情况下(触摸控件时离开屏幕),分段控件的touchesEnded
/ touchesCancelled
函数不会被调用。因此,您可以通过编程方式取消触摸:
override func viewDidDisappear(_ animated: Bool) {
segmentedControl.touchesCancelled(Set<UITouch>(), with: nil)
super.viewDidDisappear(animated)
}
override func viewWillAppear(_ animated: Bool) {
super.viewWillAppear(animated)
segmentedControl.selectedSegmentIndex = 0
}
子类化UISegmentedControl
甚至可能是更干净(但可能过大)的方法:
class SegmentedControl: UISegmentedControl {
// property to store the latest touches
private var touches: Set<UITouch>?
override func touchesBegan(_ touches: Set<UITouch>, with event: UIEvent?) {
super.touchesBegan(touches, with: event)
self.touches = touches
}
override func touchesMoved(_ touches: Set<UITouch>, with event: UIEvent?) {
super.touchesMoved(touches, with: event)
self.touches = touches
}
override func touchesEnded(_ touches: Set<UITouch>, with event: UIEvent?) {
super.touchesEnded(touches, with: event)
self.touches = nil
}
override func touchesCancelled(_ touches: Set<UITouch>, with event: UIEvent?) {
super.touchesCancelled(touches, with: event)
self.touches = nil
}
override func didMoveToWindow() {
// cancel pending touches when the view is removed from the window
if window == nil, let touches = touches {
touchesCancelled(touches, with: nil)
}
}
}
使用这种方法,您可以简单地重置viewWillAppear
中的索引:
override func viewWillAppear(_ animated: Bool) {
super.viewWillAppear(animated)
segmentedControl.selectedSegmentIndex = 0
}