Question

如果您觉得这很琐碎，我是Python的新手，很抱歉。有些电子邮件的电子邮件正文包含以下行：

Event demon log entry:

[27/12/2018 08:15:02] CAUAJM_I_40245 EVENT: ALARM ALARM: MAXRUNALARM JOB: p1_credit_qv_curve_snap MACHINE: p1prog06

使用此代码

#!/usr/bin/python

import email, imaplib, re
user = 'user@example.com'
pwd = 'pass'

conn = imaplib.IMAP4_SSL("outlook.office365.com")
conn.login(user,pwd)
conn.select("Inbox")

resp, items = conn.uid("search",None, 'All')
items = items[0].split()
for emailid in items:
    resp, data = conn.uid("fetch",emailid, "(RFC822)")
    if resp == 'OK':
        email_body = data[0][1].decode('utf-8')
        mail = email.message_from_string(email_body)
        if mail["Subject"].find("PA1") > 0 or mail["Subject"].find("PA2") > 0:
          match=re.findall(r'Event demon log entry.*\n.*\n.*', email_body , re.IGNORECASE)
           print match

我得到：

[u'Event demon log entry:\r\n\r\n[27/12/2018 08:15:02] CAUAJM_I_40245 EVENT: ALARM ALARM: MAXRUNALARM JOB: p=\r', u'Event demon log entry:<br><br=\r\n>[27/12/2018 08:15:02]      CAUAJM_I_40245 EVENT: ALARM            ALARM: M=\r\nAXRUNALARM      JOB: p1_credit_qv_curve_snap MACHINE: p1prog06<br><br>Attac=\r']

如何摆脱这些HTML输出？

我需要以下输出（如果可以在一行中显示）：

Event demon log entry:[27/12/2018 08:15:02] CAUAJM_I_40245 EVENT: ALARM ALARM: MAXRUNALARM JOB: p1_credit_qv_curve_snap MACHINE: p1prog06

Answer 1

您可以使用2个捕获组：

(\bEvent demon log entry:)(?:\r?\n|\r)+(\[[^]]+\].*)

请参见regex demo | Python demo

这将匹配：

(\bEvent demon log entry:)在第一组中捕获
(?:\r?\n|\r)+匹配新行1次以上（或使用{2}代替+精确匹配2次）
(\[[^]]+\].*)匹配[，然后匹配否定的字符类，而不是]，然后匹配结尾的]。然后匹配0+次除换行符以外的任意字符

例如，使用findall：

import re
regex = r"(\bEvent demon log entry:)(?:\r?\n|\r)+(\[[^]]+\].*)"
email_body = ("Event demon log entry:\n\n"
            "[27/12/2018 08:15:02] CAUAJM_I_40245 EVENT: ALARM ALARM: MAXRUNALARM JOB: p1_credit_qv_curve_snap MACHINE: p1prog06")

for (g1, g2) in re.findall(regex, email_body , re.IGNORECASE):
    print(g1 + g2)

在电子邮件正文中搜索字符串，然后在模式之后的字符串返回行之后返回值

1 个答案: