如何在<ul>中回显SESSION变量

Question

我有我知道可以使用的PHP SESSION变量。但是，当我尝试在它们中回显它们时，它们将不起作用。

我可以用常规代码打印SESSION变量。但是，它们不会显示在以下代码中：

<ul class="nav">
        <li class="nav-item dropdown dropdown-hover">
          <a class="nav-link dropdown-toggle pr-0" data-toggle="dropdown" 
href="#" role="button" aria-haspopup="true" aria-expanded="false">
            <i data-feather="user"></i> Hi, <?php echo $first_name; ?>  
<i data-feather="chevron-down"></i>
          </a>

我向您保证其余的代码都可以使用。我只是不知道如何在上述位置回显$ first_name。

感谢您的帮助。

Answer 1

尝试此代码。

<ul class="nav">
    <li class="nav-item dropdown dropdown-hover">
      <a class="nav-link dropdown-toggle pr-0" data-toggle="dropdown" 
href="#" role="button" aria-haspopup="true" aria-expanded="false">
        <i data-feather="user"></i> Hi, <?php echo $_SESSION['first_name']; ?>  
   <i data-feather="chevron-down"></i>
      </a>

Answer 2

创建会话

<?php
session_start();
/*session is started if you don't write this line can't use $_Session  global variable*/
$_SESSION["newsession"]=$value;
?>

参加会议

<?php
session_start();
/*session is started if you don't write this line can't use $_Session  global variable*/
$_SESSION["newsession"]=$value;
/*session created*/
echo $_SESSION["newsession"];
/*session was getting*/
?>

更新会话

<?php
session_start();
/*session is started if you don't write this line can't use $_Session  global variable*/
$_SESSION["newsession"]=$value;
/*it is my new session*/
$_SESSION["newsession"]=$updatedvalue;
/*session updated*/
?>

删除会话

<?php
session_start();
/*session is started if you don't write this line can't use $_Session  global variable*/
$_SESSION["newsession"]=$value;
unset($_SESSION["newsession"]);
/*session deleted. if you try using this you've got an error*/
?>

Answer 3

还请检查您的会话是否开始

您应该使用$ _SESSION ['var_name']; 像$ _SESSION ['first_name'];

或使用提取函数将first_name用作变量。