Question

我正在尝试执行以下查询：

select *
from A
where id in (
    (select id from A where created_at >= '2018-12-25' order by created_at asc limit 1)
    union
    (select id from A where created_at < '2018-12-26' order by created_at desc limit 1)
)

我用knex尝试过的是：

knex.select('*')
  .from('A')
  .whereIn('id', qb => 
    qb.select('*')
      .from('A')
      .where('created_at', '>=', '2018-12-25')
      .orderBy('created_at', 'ASC')
      .limit(1)
      .union(qb =>
        qb.select('*')
          .from('A')
          .where('created_at', '<', '2018-12-26')
          .orderBy('created_at', 'DESC')
          .limit(1)
      )
  )

但是它会产生不同的SQL：

select *
from "A"
where "id" in (select * from "A" where "created_at" >= ? union select * from "A" where "created_at" < ? order by "created_at" DESC limit ? order by "created_at" ASC limit ?)

似乎order by子句没有按照我想要的方式处理，而且括号组也不相同。我这是什么错如何使用knex正确执行操作？

Answer 1

以下操作将输出您所需的sql，但我想它不是执行操作的有效方法。

const sql = knex.select('*')
   .from('A')
   .whereIn('id', qb =>
      qb.union(qb =>
            qb.select('*')
               .from('A')
               .where('created_at', '>=', '2018-12-25')
               .orderBy('created_at', 'ASC')
               .limit(1)
         )
         .union(qb =>
            qb.select('*')
               .from('A')
               .where('created_at', '<', '2018-12-26')
               .orderBy('created_at', 'DESC')
               .limit(1)
         , false)
   )
   .toSQL();
console.log(sql) ;

带联合和限制的knex子查询

1 个答案: