String ACCESS_CODE = "My_PAYFORTAcces_Code"
String MERCHANT_ID = "My_Payfory_Merchet_ID"
我发现了我认为该问题与签名生成有关,
我尝试使用字符串生成签名
“ TESTSHAINaccess_code=ACCESS_CODEdevice_id=ffffffff-d6ab-d802-b274-478d7792a1b7language=enmerchant_identifier=MERCHANT_IDservice_command=SDK_TOKENTESTSHAIN
”的签名为“ 9c804f2c08e36749c75389afc12c50e68307c31052e6434c072cd5b36cc8c607
”,当我尝试使用“ PASSaccess_code=ACCESS_CODElanguage=enmerchant_identifier=MERCHANT_IDmerchant_reference=53469903-eaac-459c-91b9-78cb026b0712service_command=TOKENIZATIONPASS
”的签名为“ 4568f58e22f46b75fb6157cbc131ab194e1f9a066bdc501171a018d2c1d22e14
”。
一旦我尝试使用两个签名生成sdk_token
,我就会得到“ {"response_code":"00008","response_message":"Signature mismatch","service_command":"SDK_TOKEN","device_id":"ffffffff-d6ab-d802-b274-478d7792a1b7","signature":"30eb8f03adc12dd714aac83249ad0b3e763cfadcd6c996bdf49d86125c23335","merchant_identifier":"My_Payfory_Merchet_ID","access_code":"My_PAYFORTAcces_Code","language":"en","status":"00"}
”
这是我用于生成签名的代码,请检查并让我知道其正确与否,
@TargetApi(Build.VERSION_CODES.KITKAT)
public static String generateSHA256(String text) throws NoSuchAlgorithmException, UnsupportedEncodingException {
MessageDigest md = MessageDigest.getInstance("SHA-256");
byte[] textBytes = text.getBytes(StandardCharsets.UTF_8);
md.update(textBytes, 0, textBytes.length);
byte[] sha1hash = md.digest();
return convertToHex(sha1hash);
}
private static String convertToHex(byte[] data) {
StringBuilder buf = new StringBuilder();
for (byte b : data) {
int halfbyte = (b >>> 4) & 0x0F;
int two_halfs = 0;
do {
buf.append((0 <= halfbyte) && (halfbyte <= 9) ? (char) ('0' + halfbyte) : (char) ('a' + (halfbyte - 10)));
halfbyte = b & 0x0F;
} while (two_halfs++ < 1);
}
return buf.toString();
}
答案 0 :(得分:0)
这解决了我的问题,
我更改了字符串以生成签名,
Constants.PayfortRequestPhrase + "access_code=" + Constants.PayfortAccessCode
+ "device_id=" + deviceId + "language=enmerchant_identifier=" +
Constants.PayfortMerchantIdentifier + "service_command=SDK_TOKEN" + Constants.PayfortRequestPhrase
RequestPhrase
,AccessCode
和MerchantIdentifier
是我从Pay-fort帐户获得的。并且签名生成代码保持不变。
答案 1 :(得分:0)
这对 Apple Pay 的制作没有问题。
public function createSignature($deviceId){
$requestPhrase = PaymentHelper::paymentInfo('ap_request_phrase');
$access_code = PaymentHelper::paymentInfo('ap_access_code');
$merchant_identifier = PaymentHelper::paymentInfo('merchant_identifier');
if (YII_ENV_DEV) {
$seckey = '86qCkwevMaIwR3wFnilov.&(';
} else {
$seckey = $requestPhrase;
}
$sdkCredentials = [
'service_command' => 'SDK_TOKEN',
'merchant_identifier' => $merchant_identifier,
'language' => $this->language,
'device_id' => $deviceId,
'access_code' => $access_code,
];
$arrData = $sdkCredentials;
$shaString = '';
ksort($arrData);
foreach ($arrData as $key => $value) {
$shaString .= "$key=$value";
}
$shaString = $seckey . $shaString . $seckey;
$signature = hash("sha256", $shaString);
$sdkCredentials['signature'] = $signature;
return $sdkCredentials;
}