函数调用不执行其定义

Question

我希望就与此功能相关的事项提出建议。

我已经尝试过对代码进行各种编辑和缩进，但是显示的结果相同。

它显示了NameError: name 'sentence' is not defined，尽管我已经在函数中定义了它。

代码是：

def about (name, age, likes):
  sentence = "Meet {}, he is {} years old and likes {}".format(name,age,likes)
  return sentence

about ("Jack", 23, "programming")
print (sentence)

Answer 1

您应该调用函数并将其分配给变量：

def about(name, age, likes):
    sentence = "Meet {}, he is {} years old and likes {}".format(name,age,likes)
    return sentence

然后

val = about("Jack", 23, "programming")
print(val)

您也可以使用sentence代替val，但这在功能范围上不会是sentence。

Answer 2

立即尝试。...

def about (name, age, likes):
    sentence = "Meet {}, he is {} years old and likes {}".format(name,age,likes)
    return sentence

print(about('rohit',23,'programming'))

sentense范围已绑定到about函数...并且尝试将其打印出该函数范围可能不起作用。