Question

我想从数据库中获取一行并显示在我的页面中。以下代码无效，我的浏览器挂起。而且我不知道如何解决。请帮助我。

班级

public function get_calculate($id)
{
    if ($id != 0) {
        $stmt_select_calculate = $this->connect()->prepare('SELECT analix_calculate.title,analix_calculate.basis FROM analix_calculate where analix_calculate.id=:calculate_id AND analix_calculate.is_active=1;');
        $stmt_select_calculate->bindValue(':calculate_id', $id, PDO::PARAM_STR);
    } else {
        $stmt_select_calculate = $this->connect()->prepare('SELECT analix_calculate.title,analix_calculate.basis FROM analix_calculate where analix_calculate.is_active=1;');
    }
    return $stmt_select_calculate->execute();
}

index.php：

<?php
include("../db/Database.php");
$databse = new Database();
$menu = $databse->get_calculate(0);
while ($row_select_calculate = $menu) {
?>
    <li>
        <a href="#0">
        <i class="fa fa-home" aria-hidden="true"></i><?php echo $row_select_calculate['title']?>
        </a>
    </li>
<?php
}
?>

Answer 1

首先，$stmt_select_calculate->execute(); returns布尔值。很明显，您不能迭代布尔值。因此，您应该返回语句对象本身：

public function get_calculate($id)
{
    if ($id != 0) {
        $stmt_select_calculate = $this->connect()->prepare('SELECT analix_calculate.title,analix_calculate.basis FROM analix_calculate where analix_calculate.id=:calculate_id AND analix_calculate.is_active=1;');
        $stmt_select_calculate->bindValue(':calculate_id', $id, PDO::PARAM_STR);
    } else {
        $stmt_select_calculate = $this->connect()->prepare('SELECT analix_calculate.title,analix_calculate.basis FROM analix_calculate where analix_calculate.is_active=1;');
    }
    $stmt_select_calculate->execute();
    return $stmt_select_calculate;
}

在index.php中，您应该fetch数据：

$menu_stmt = $databse->get_calculate(0);
while ($row = $menu_stmt->fetch()) {
?>
    <li>
        <a href="#0">
        <i class="fa fa-home" aria-hidden="true"></i><?php echo $row['title']?>
        </a>
    </li>
<?php
}

按类获取用户数据信息（php）

1 个答案: