Question

我是Java编程的新手。

我想获取某些给定字符串的sha-256哈希。

我得到：

㔴晥㜶晥㜶㔴㄰扡㔴晥㄰扡㌲㌲㌲㄰摣㔴㜶㌲扡扡㌲㄰㄰㌲㜶㜶晥㔴㄰

但是期望像这样：

074cfbbad12bade66c92d01142b83c8f2b24030959980151f83972f4575a43e1

这是我的代码：

import java.security.MessageDigest;
import java.security.NoSuchAlgorithmException;

public class HelloWorld{

    private static final char[] DIGITS;    
    static {
        char[] arrc;
        char[] arrc2 = arrc = new char[16];
        arrc2[0] = 12592;
        arrc2[1] = 13106;
        arrc2[2] = 13620;
        arrc2[3] = 14134;
        arrc2[4] = 14648;
        arrc2[5] = 25185;
        arrc2[6] = 25699;
        arrc2[7] = 26213;
        DIGITS = arrc;
    }

     public static void main(String []args){
        StringBuilder localStringBuilder = new StringBuilder();
        localStringBuilder.append(55);
        localStringBuilder.append("market-gap");
        localStringBuilder.append("marjet-gre");
        localStringBuilder.append("1");
        localStringBuilder.append("05/19/1989");
        localStringBuilder.append("6.3.0");
        localStringBuilder.append("0");
        localStringBuilder.append("");
        localStringBuilder.append("en");
        localStringBuilder.append("");
        localStringBuilder.append("00e0533117bb8707");
        String paramString1 = localStringBuilder.toString();

        String strrrr = sha256(paramString1);

        System.out.println(strrrr);
     }

     public static String encodeHex(byte[] arrby) {
        StringBuilder stringBuilder = new StringBuilder(arrby.length * 2);
        for (int i = 0; i < arrby.length; ++i) {
            stringBuilder.append(DIGITS[(arrby[i] & 240) >>> 4]);
            stringBuilder.append(DIGITS[arrby[i] & 15]);
        }
        return stringBuilder.toString();
    }
    public static String sha256(String paramString)
      {
        try
        {
          MessageDigest localMessageDigest = MessageDigest.getInstance("SHA-256");
          return encodeHex(localMessageDigest.digest(paramString.getBytes()));
        }
        catch (NoSuchAlgorithmException e)
        {
          //ThrowableExtension.printStackTrace(e);
        }
        return null;
      }
}

我在这里做错了什么？

致谢

Answer 1

您的十六进制编码器看起来非常可疑。它应该如何工作？

您可以尝试JDK中已经存在的转换器：

public static String sha256(String paramString) {
    try {
        MessageDigest localMessageDigest = MessageDigest.getInstance("SHA-256");
        byte[] binaryDigest = localMessageDigest.digest(paramString.getBytes());
        return DatatypeConverter.printHexBinary(binaryDigest);
    } catch (NoSuchAlgorithmException e) {
        // ThrowableExtension.printStackTrace(e);
    }
    return null;
}

编辑：

好的，知道了。

您的DIGITS值错误。这是一个工作版本：

public class HelloWorld {

private static final char[] DIGITS = { '0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C', 'D', 'E', 'F' };

    public static void main(String[] args) {
        StringBuilder localStringBuilder = new StringBuilder();
        localStringBuilder.append(55);
        localStringBuilder.append("market-gap");
        localStringBuilder.append("marjet-gre");
        localStringBuilder.append("1");
        localStringBuilder.append("05/19/1989");
        localStringBuilder.append("6.3.0");
        localStringBuilder.append("0");
        localStringBuilder.append("");
        localStringBuilder.append("en");
        localStringBuilder.append("");
        localStringBuilder.append("00e0533117bb8707");
        String paramString1 = localStringBuilder.toString();

        String strrrr = sha256(paramString1);

        System.out.println(strrrr);
    }

    public static String encodeHex(byte[] arrby) {
        StringBuilder stringBuilder = new StringBuilder(arrby.length * 2);
        for (int i = 0; i < arrby.length; ++i) {
            stringBuilder.append(DIGITS[(arrby[i] & 0xF0) >>> 4]);
            stringBuilder.append(DIGITS[arrby[i] & 0x0F]);
        }
        return stringBuilder.toString();
    }

    public static String sha256(String paramString) {
        try {
            MessageDigest localMessageDigest = MessageDigest.getInstance("SHA-256");
            return encodeHex(localMessageDigest.digest(paramString.getBytes()));
        } catch (NoSuchAlgorithmException e) {
            // ThrowableExtension.printStackTrace(e);
        }
        return null;
    }

}

此外，出于可读性考虑，我将整数240和15更改为0xF0和0x0F。

产生奇怪字符串而不是SHA-256字符串的十六进制编码器方法

1 个答案: