水平返回数据

Question

我有点迷失在这里。

我有一个表，该表在同一列中包含多个重复值，我想以S / N和Group作为一个唯一值返回，然后将每个包装的价格在单独的列中显示为（'1D'AS DAILY，'每周1W”，“每月1M”。

上午使用MS SQL 2012

预先感谢

致谢， 阿德南

Answer 1

select [S/N], [group],
       sum(case when package = '1D' then price else 0 end) as [daily price],
       sum(case when package = '1W' then price else 0 end) as [weekly price],
       sum(case when package = '1M' then price else 0 end) as [monthly price]
from rates
group by [S/N], [group]

Answer 2

您还可以使用PIVOT运算符：

if OBJECT_ID('tempdb..#Rates') is not NULL  drop table #Rates

create table #Rates(
    S_N  int not null,
    _group varchar(10) not null,
    Package char(2) not null,
    price int not null
)

insert into #Rates
values (8, 'D'   , '1M', 3700)
,(8, 'I-DC','1M', 1750)
,(8,  'TB', '1M', 7000)
,(12, 'A', '1D', 80)
,(12, 'A', '1W', 480)
,(12, 'A', '1M', 1800)
,(12, 'B', '1D', 90)
,(12, 'B', '1W', 540)
,(12, 'B', '1M', 2100)

select S_N, _group, pvt.[1D] as "DailyPrice1D", pvt.[1W] as "WeeklyPrice1W", pvt.[1M] as "MonthlyPrice1M"
from #Rates
pivot(avg(price) FOR Package in ("1D", "1W", "1M")) pvt
ORDER by S_N

您是否需要更多说明，或者此代码示例足够？ 有关更多信息，请参见Microsoft文档：https://docs.microsoft.com/en-us/sql/t-sql/queries/from-using-pivot-and-unpivot?view=sql-server-2017