Question

我有三个包含不同值模式的列表。这应该仅根据某些if条件在单个字典内附加特定值。我尝试了以下方法，但我从列表中得到了所有值。

class_list = [1,2,3,4,5,6]

boxes = [[0.1,0.2,0.3,0.4],[0.5,0.7,0.8,0.9],[0.7,0.9,0.4,0.2],[0.9,0.7,0.6,0.3],[0.9,0.14,0.6,0.3],[0.9,0.7,0.6,0.13]]

scores = [0.98,0.87,0.97,0.96,0.94,0.92]

k=1;

data = {}

for a in scores:
    for b in boxes:
        for c in list:
            if a >= 0.98:
                data[k+1] = {"score":a,"box":b, "class": c } ;
                k=k+1;
print("Final_result",data)

Answer 1

也许使用zip：

for a,b,c in zip(scores,boxes,class_list):
   if a >= 0.98:
       data[k+1] = {"score":a,"box":b, "class": c } ;
       k=k+1;
print("Final_result",data)

输出：

Final_result {2: {'score': 0.98, 'box': [0.1, 0.2, 0.3, 0.4], 'class': 1}}

编辑：

for a,b,c in zip(scores,boxes,class_list):
   if a >= 0.98:
       data[k+1] = {"score":a,"box":b, "class": int(c) } ;
       k=k+1;
print("Final_result",data)

Answer 2

获得所有值是因为您将所有其他值（即6x6x6次）遍历所有值。我了解您的问题，您需要使用的是Zip功能。

llist = [1,2,3,4,5,6]

boxes = [[0.1,0.2,0.3,0.4],[0.5,0.7,0.8,0.9],[0.7,0.9,0.4,0.2],[0.9,0.7,0.6,0.3],[0.9,0.14,0.6,0.3],[0.9,0.7,0.6,0.13]]

scores = [0.98,0.87,0.97,0.96,0.94,0.92]

k=1;

data = {}



for a,b,c in zip(scores, boxes, llist):
    if a >= 0.98:
        data[k] = {"score":a,"box":b, "class": c } ;
        k = k + 1

for k in data.keys():
    print(k , data[k])

ps：避免使用关键字命名变量，列表是关键字。可能会遇到问题，甚至可以找到原因。

将不同的列表值应用于python中的字典

2 个答案: