ASP.NET Web API2：如何将图像保存到数据库

Question

我的代码将图像保存到数据库中，而其他数据将被忽略。

型号： 我的表名是一篇文章，其属性是 articleId，文章名称，文章图片和状态。

     [HttpPost]
    public async Task<HttpResponseMessage> Postdata()
    {
        article obj = new article();
        List<string> savedFilePath = new List<string>();
        // Check if the request contains multipart/form-data
        if (!Request.Content.IsMimeMultipartContent())
        {
            throw new HttpResponseException(HttpStatusCode.UnsupportedMediaType);
        }
        //Get the path of folder where we want to upload all files.
        string rootPath = HttpContext.Current.Server.MapPath("~/Uploads");
        var provider = new MultipartFileStreamProvider(rootPath);
        // Read the form data.
        //If any error(Cancelled or any fault) occurred during file read , return internal server error
        var task = Request.Content.ReadAsMultipartAsync(provider).
            ContinueWith<HttpResponseMessage>(t =>
            {
                if (t.IsCanceled || t.IsFaulted)
                {
                    Request.CreateErrorResponse(HttpStatusCode.InternalServerError, t.Exception);
                }
                foreach (MultipartFileData dataitem in provider.FileData)
                {
                    try
                    {
                        //Replace / from file name
                        string name = dataitem.Headers.ContentDisposition.FileName.Replace("\"", "");
                        //Create New file name using GUID to prevent duplicate file name
                        string newFileName = Guid.NewGuid() + Path.GetExtension(name);
                        //Move file from current location to target folder.
                        File.Move(dataitem.LocalFileName, Path.Combine(rootPath, newFileName));
                        string articlename = dataitem.Headers.ContentDisposition.Name;
                        string articlesutus = dataitem.Headers.ContentDisposition.FileNameStar;
                        obj.articleimage = newFileName;
                        obj.articlename = articlename;
                        obj.articlestatus = articlesutus;
                        _context.SaveChanges();
                    }
                    catch (Exception ex)
                    {
                        string message = ex.Message;
                    }
                }


                return Request.CreateResponse(HttpStatusCode.Created, savedFilePath);
            });
        return await task;
    }