Question

此代码在remix上的版本0.4.24上运行，但在版本0.5.0+上未运行，我也尝试在Windows 10上使用松露编译它，这也给出了异常。

pragma solidity ^0.5.0;

contract lottery {

    address public manager;
    address[] public players;

    constructor() public{
        manager = msg.sender;
    }

    modifier restricted(){
        require(msg.sender == manager);
        _;
    }

    function enterLottery() public payable {
        require(msg.value > 0.01 ether);
        players.push(msg.sender);
    }

    function random() public view returns(uint) {
        return uint(keccak256(abi.encodePacked(block.difficulty,now,players)));
    }

    function pickWinner() public restricted{

        uint index = random() % players.length;
        address winner = players[index];
        players = new address[](0);

        winner.transfer(address(this).balance);
    }

    function getPlayers() public view returns(address[] memory){
        return players;
    }  
}

winner.transfer(address(this).balance);不起作用。我还支付了pickWinner()，但这并不能解决错误

Answer 1

感谢上帝，我发现了我所缺少的。坚固度0.5.3：地址类型有两种：地址和应付地址：与地址相同，但其他成员可以转移和发送。 enter link description here

创建“地址可支付的玩家数组” 例如应付地址[]公共参与者；还将getPlayers（）返回数据类型更改为地址播放器[]

如何解决<address> .transfer例外：找不到成员转移？

1 个答案: