Question

我在DRF中的视图集有问题：

def get_queryset(self):
    """
    :return: filtered queryset based on request query_param

    """
    # todo#amedeo: improve the readability code
    qs = super(ChecklistViewSet, self).get_queryset()
    _pk = self.kwargs['pk']

    if self.request.method == 'PUT':
        instance = qs.filter(pk=int(_pk)).first()
        # pass in the instance we want to update
        serializer = ChecklistSerializer(instance, self.request.data)

        # validate and update
        if serializer.is_valid():
            serializer.save()
            serializer_dict = serializer.data
            serializer_dict["message"] = "Checklist updated successfully."
            return response.Response(serializer_dict, status=status.HTTP_200_OK)

        else:
            return response.Response(serializer.errors, status=status.HTTP_400_BAD_REQUEST)

在我的代码中objetc已保存，但是响应给出了一个错误消息：

AttributeError：“响应”对象没有属性“模型”

我的序列化器是：

class ChecklistSerializer(serializers.ModelSerializer):

class Meta:
    model = Checklist
    fields = ('id', 'approved_by', 'role', 'hardship_classification',
              'total_capacity', 'capacity_for_residents', 'checklist_type',
              'state', 'pdf', 'submitting_afp', 'disabled', 'location')

我通过传递json的客户端PUT方法调用：

{
"approved_by": "Test",
"role": "test_role_4",
"hardship_classification": "test_6",
"total_capacity": "50",
"capacity_for_residents": "350",
"checklist_type": "permanent",
"state": "qcl_draft",
"pdf": null,
"submitting_afp": 3999,
"disabled": false,
"location": 97
}

但是我发现了这个错误。该模型已保存，但Response给我错误

内部服务器错误：/ api / v1 / checklists / 3 / 追溯（最近一次通话）：在内部的文件“ /home/adifilippo/.envs/accomodation/local/lib/python2.7/site-packages/django/core/handlers/exception.py”，第41行响应= get_response（请求）文件_get_response中的第187行“ /home/adifilippo/.envs/accomodation/local/lib/python2.7/site-packages/django/core/handlers/base.py” 响应= self.process_exception_by_middleware（e，请求） _get_response中的文件“ /home/adifilippo/.envs/accomodation/local/lib/python2.7/site-packages/django/core/handlers/base.py”，行185 响应= wraped_callback（请求，* callback_args，** callback_kwargs）文件“ /home/adifilippo/.envs/accomodation/local/lib/python2.7/site-packages/django/views/decorators/csrf.py”，第58行，在wrapped_view中返回view_func（* args，** kwargs）在视图中的文件“ /home/adifilippo/.envs/accomodation/local/lib/python2.7/site-packages/rest_framework/viewsets.py”中，第116行返回self.dispatch（request，* args，** kwargs）派发文件“ /home/adifilippo/.envs/accomodation/local/lib/python2.7/site-packages/rest_framework/views.py”，行495 响应= self.handle_exception（exc）文件“ /home/adifilippo/.envs/accomodation/local/lib/python2.7/site-packages/rest_framework/views.py”，行455，位于handle_exception中 self.raise_uncaught_exception（exc）派发文件“ /home/adifilippo/.envs/accomodation/local/lib/python2.7/site-packages/rest_framework/views.py”，第483行 self.initial（请求，* args，** kwargs）最初的文件“ /home/adifilippo/.envs/accomodation/local/lib/python2.7/site-packages/rest_framework/views.py”，第401行 self.check_permissions（请求）文件“ /home/adifilippo/.envs/accomodation/local/lib/python2.7/site-packages/rest_framework/views.py”，行334，在check_permissions中如果没有permission.has_permission（请求，自我）：在has_permission中的第206行，文件“ /home/adifilippo/.envs/accomodation/local/lib/python2.7/site-packages/rest_framework/permissions.py” 烫发= self.get_required_permissions（request.method，queryset.model） AttributeError：“响应”对象没有属性“模型” “ PUT / api / v1 / checklists / 3 / HTTP / 1.1” 500 42934

在此处输入代码

Answer 1

get_queryset方法应返回queryset而不是Response，并且在put方法中应覆盖更新操作。在此处class-based-views中阅读并 filtering了解更多详情。可能是您需要删除get_queryset覆盖并仅添加put方法，如下所示：

def put(self, request, pk, format=None):
    instance = self.get_object(pk)
    # pass in the instance we want to update
    serializer = ChecklistSerializer(instance, self.request.data)

    # validate and update
    if serializer.is_valid():
        serializer.save()
        serializer_dict = serializer.data
        serializer_dict["message"] = "Checklist updated successfully."
        return response.Response(serializer_dict, status=status.HTTP_200_OK)

    else:
        return response.Response(serializer.errors, status=status.HTTP_400_BAD_REQUEST)

Answer 2

你可以这样做

from django.shortcuts import get_objects_or_404

class YourAPIView(ModelViewSet):
   def put(self, request, pk):
       instance = get_objects_or_404(YourModel, pk=pk)
       serializer = ChecklistSerializer(instance, self.request.data)

# validate and update
       if serializer.is_valid():
           serializer.save()
           serializer_dict = serializer.data
           serializer_dict["message"] = "Checklist updated successfully."
           return response.Response(serializer_dict, status=status.HTTP_200_OK)
       return response.Response(serializer.errors, status=status.HTTP_400_BAD_REQUEST)

Django Rest Framework：序列化程序响应错误

2 个答案: