Question

我正在从mysql命令行更新表..更新没有发生..

表说明如下：

mysql> describe userdailycalorie;
+-------------------+----------+------+-----+---------+-------+
| Field             | Type     | Null | Key | Default | Extra |
+-------------------+----------+------+-----+---------+-------+
| id                | int(11)  | NO   | PRI | NULL    |       |
| balanced_diet     | bit(1)   | YES  |     | NULL    |       |
| calories_consumed | double   | YES  |     | NULL    |       |
| date              | datetime | YES  |     | NULL    |       |
| user_id           | int(11)  | YES  | MUL | NULL    |       |
+-------------------+----------+------+-----+---------+-------+
5 rows in set (0.13 sec)

对应的表内容如下：

mysql> select * from userdailycalorie;
+----+---------------+-------------------+---------------------+---------+
| id | balanced_diet | calories_consumed | date                | user_id |
+----+---------------+-------------------+---------------------+---------+
| 16 |               |                 0 | 2018-02-02 00:00:00 |       3 |
+----+---------------+-------------------+---------------------+---------+
1 row in set (0.00 sec)

相应的Update语句如下：

mysql> update userdailycalorie  set calories_consumed= 205.4  and balanced_diet =true WHERE user_id = 3;
Query OK, 0 rows affected (0.00 sec)
Rows matched: 1  Changed: 0  Warnings: 0

匹配的行是1，表示它选择了该行。.更新未按更改进行：0 ..我不确定为什么，...有人可以帮我调试此问题吗？

Answer 1

如果要更新两个不能使用AND的字段，请用逗号,分隔每个要更新的字段

update userdailycalorie  
set calories_consumed = 205.4  
  , balanced_diet = true 
WHERE user_id = 3;

Answer 2

您可以在下面尝试-

update userdailycalorie  
set calories_consumed= 205.4, balanced_diet =1
WHERE user_id = 3;

匹配的行：1已更改：0警告：0 Mysql更新未发生

2 个答案: