我有一个像这样的json
[
{
"Id": "1234",
"stockDetail": [
{
"Number": "10022_1",
"Code": "500"
},
{
"Number": "10022_1",
"Code": "600"
}
]
},
{
"Id": "1235",
"stockDetail": [
{
"Number": "10023_1",
"Code": "100"
},
{
"Number": "10023_1",
"Code": "100"
}
]
}
]
如何在sql表中将其转换,如下所示:
+------+---------+------+
| Id | Number | Code |
+------+---------+------+
| 1234 | 10022_1 | 500 |
| 1234 | 10022_1 | 600 |
| 1235 | 10023_1 | 100 |
| 1235 | 10023_1 | 100 |
+------+---------+------+
答案 0 :(得分:3)
在您的情况下,您可以尝试将JSON子节点与父节点交叉应用:
DECLARE @json nvarchar(max)
SET @json = N'
[
{
"Id": "1234",
"stockDetail": [
{
"Number": "10022_1",
"Code": "500"
},
{
"Number": "10022_1",
"Code": "600"
}
]
},
{
"Id": "1235",
"stockDetail": [
{
"Number": "10023_1",
"Code": "100"
},
{
"Number": "10023_1",
"Code": "100"
}
]
}
]'
SELECT
JSON_Value (i.value, '$.Id') as ID,
JSON_Value (d.value, '$.Number') as [Number],
JSON_Value (d.value, '$.Code') as [Code]
FROM OPENJSON (@json, '$') as i
CROSS APPLY OPENJSON (i.value, '$.stockDetail') as d
输出:
ID Number Code
1234 10022_1 500
1234 10022_1 600
1235 10023_1 100
1235 10023_1 100
答案 1 :(得分:3)
如果需要定义类型化的列,则可以将OPENJSON
与WITH
子句一起使用:
DECLARE @j nvarchar(max) = N'[
{
"Id": "1234",
"stockDetail": [
{ "Number": "10022_1",
"Code": "500"
},
{ "Number": "10022_1",
"Code": "600"
}
]
},
{
"Id": "1235",
"stockDetail": [
{ "Number": "10023_1",
"Code": "100"
},
{ "Number": "10023_1",
"Code": "100"
}
]
}
]'
select father.Id, child.Number, child.Code
from openjson (@j)
with (
Id int,
stockDetail nvarchar(max) as json
) as father
cross apply openjson (father.stockDetail)
with (
Number nvarchar(100),
Code nvarchar(100)
) as child
结果: