Question

我正在将PHP中的json_encoded数组返回给我的Android客户端。我首先从服务器收集数据，然后将其输入到名为“数据”的数组中：

$data[] = array('name'=>$name, 'distance'=>(int)$distance, 'city'=>$city, 'state'=>$state, 'interest'=>$interest, 'avatar'=>$avatar);

然后，我将该数组放入另一个数组中以获取一个count变量，这只是我的for循环中的增量。看起来像这样：

$response = array('data'=>$data, 'count'=>$count);

在Android方面，我使用以下方法检索此信息：

StringRequest searchPostRequest = new StringRequest(Request.Method.POST, searchURL, new Response.Listener<String>() {
            @Override
            public void onResponse(String response) {
                try {
                    mPlayerSuccess.start();
                    Log.d(TAG, "Complete Response: "+response);
                    JSONObject object = new JSONObject(response);
                    /*
                     *GET THE COMPLETE JSON ARRAY FROM SERVER
                     * ARRAY NAME IS "data"
                     * Strings are name, distance, city, state, interest, avatar
                     */
                    JSONArray array = object.getJSONArray("data");
                    for(int i = 0; i < array.length(); i++) {
                        JSONObject jsonObject = array.getJSONObject(i);
                        String name = jsonObject.getString("name");
                        int distance = jsonObject.getInt("distance");
                        String city = jsonObject.getString("city");
                        String state = jsonObject.getString("state");
                        String interest = jsonObject.getString("interest");
                        String avatar = jsonObject.getString("avatar");
                        String formatted_avatar = avatar.replace("\\", "");
                        int count = jsonObject.getInt("count");

                        Log.d(TAG, "Name Returned: "+name);
                        Log.d(TAG, "Distance Returned: "+distance);
                        Log.d(TAG, "City Returned: "+city);
                        Log.d(TAG, "State Returned: "+state);
                        Log.d(TAG, "Interest Returned: "+interest);
                        Log.d(TAG, "Avatar Returned: "+formatted_avatar);
                        Log.d(TAG, "Count: "+count);

这返回（在我的日志中）：

D/MainActivity: Complete Response: {"data":[{"name":"lgill10","distance":296,"city":"Clinton","state":"IL","interest":"3D printing","avatar":"..\/users\/lgill10\/uploads\/dj-franklin.jpg"},{"name":"lgill9","distance":316,"city":"Bloomington","state":"IL","interest":"3D printing","avatar":"css\/images\/user_default\/default_avatar.png"},{"name":"testuser2","distance":14,"city":"Jonesboro","state":"AR","interest":"3D printing","avatar":"css\/images\/user_default\/default_avatar.png"}],"count":3}

但是，我得到的是“没有计数价值”，这导致所有“ Log.d”消息都无法显示。

我还尝试使用以下方法提取计数：

JSONArray count_array = object.getJSONArray("count");
JSONObject countObject = count_array.getJSONObject(0);
int count = countObject.getInt("count");

但是随后它捕获到异常并告诉我：

Value 3 at count of type java.lang.Integer cannot be converted to JSONArray

它返回正确的计数（3），但我不知道如何从多维数组中正确提取它。

如何获取计数值？我觉得这是一个小语法问题，我只是不知道如何纠正它。

Answer 1

我希望我在问之前会想到这一点，但它只是突然出现在我身上。由于count变量实际上是数组长度，因此我使用以下命令进行访问：

  ...
  Modelica.SIunits.Time t_star=-1;
equation
  when p >= p_set then
    t_star = time;
  end when;
  A = if t_star<0 then A_max else min(const*(t - t_star) + A_0, A_max);

返回：

int count = array.length();
Log.d(TAG, "Count: "+count);

如何在Volley中解析多维json数组？

1 个答案: