Question

我想从json中删除一些值。 json格式如下：

{
    "cod": "200",
    "message": 0.0135,
    "cnt": 40,
    "list": [
        {
            "dt": 1545598800,
            "main": {
                "temp": 267.03,
                "temp_min": 258.629,
                "temp_max": 267.03,
                "pressure": 741.31,
                "sea_level": 1034.85,
                "grnd_level": 741.31,
                "humidity": 72,
                "temp_kf": 8.4
            },
            "weather": [
                {
                    "id": 800,
                    "main": "Clear",
                    "description": "clear sky",
                    "icon": "01n"
                }
            ]
}

我想从json中删除一些数据。如何在天气中删除ID，图标？我尝试这个：

(ObjectNode) rootNode.get("list").get(i).get("weather")).remove("id");

但它不正确，并且会发生此错误：

com.fasterxml.jackson.databind.node.ArrayNode cannot be cast to com.fasterxml.jackson.databind.node.ObjectNode

Answer 1

问题是rootNode.get("list").get(i).get("weather")将返回weather数组

"weather": [
            {
                "id": 800,
                "main": "Clear",
                "description": "clear sky",
                "icon": "01n"
            }
        ]

然后获取第一个ObjectNode并删除id

(ObjectNode) rootNode.get("list").get(i).get("weather").get(0).remove("id");

Answer 2

尝试以下代码可能会起作用。首先将JsonNode转换为ObjectNode

JsonNode yourJsonNode;
List<String> fieldsTobeRemoved = Arrays.asList("a","b");
if (!yourJsonNode.isMissingNode() && yourJsonNode instanceof ObjectNode && null != fieldsTobeRemoved) {
    ObjectNode yourObjectNode = (ObjectNode) yourJsonNode;
    fieldsToBeRemoved.forEach(field -> yourObjectNode.remove(field));
}

如何从json使用Objectnode中删除特定元素？

2 个答案: