Question

我想使用输入日期（2018-12-05）将其转换为时间戳格式（2018-12-05 00:00:00），以便可以将此时间戳与我的数据库时间戳进行比较。这样做吗？

我尝试按照代码中的说明转换日期格式，但出现此错误。

<table class="table table-borderless table-data3">
<h3>Expense Table</h3>
<br>
<thead>
    <tr>
        <th>Title</th>
        <th>Amount</th>                           
        <th>Amount</th>                           
    </tr>
</thead>
<tbody>
    <?php

    if(isset($_POST['submit'])){
        $connect = new PDO("mysql:host=localhost;dbname=inventory_management_system", "root", "");
        //get input in date format like 2018-12-05
        $start_date=$_POST['start_date'];
        $end_date=$_POST['end_date'];
        $time = new DateTime('00:00:00');

        //convert date to timestamp format like 2018-12-05 00:00:00
        $date1 = new DateTime($start_date);
        $sdate = new DateTime($date1->format('Y-m-d') .' ' .$time->format('H:i:s'));
        $strDate = $sdate->format('Y-m-d H:i:s'); // Outputs like '2017-03-14 00:00:00'

        $date2 = new DateTime($end_date);
        $edate = new DateTime($date2->format('Y-m-d') .' ' .$time->format('H:i:s'));
        $endDate = $edate->format('Y-m-d H:i:s'); // Outputs like '2017-03-14 00:00:00''

        //get data between the two converted date $sdate and $edate
        $query='select amount,date from pl_per_day where STR_TO_DATE(date,"%Y-%m-%d %T")>=STR_TO_DATE($strDate,"%Y-%m-%d") AND STR_TO_DATE(date,"%Y-%m-%d %T")<=STR_TO_DATE($endDate,"%Y-%m-%d")';
                $query_run=mysqli_query($connect , $query);
                while($row=mysqli_fetch_array($query_run))
                    {
                        $moddate=strtotime($row['date']);
    ?>

    <tr>
        <td><?php echo $amount; ?></td>
        <td><?php echo $moddate; ?></td>


    <?php }  } ?>
    </tr>
</tbody>

Answer 1

在您的PHP脚本中，$ sdate和$ edate是DateTime类的对象。您应该从如下对象中获取字符串值； -您的代码

$sdate = new DateTime($date1->format('Y-m-d') .' ' .$time->format('H:i:s'));
$sdate->format('Y-m-d H:i:s'); // Outputs like '2017-03-14 00:00:00'

修复

$sdate = new DateTime($date1->format('Y-m-d') .' ' .$time->format('H:i:s')); $strDate = $sdate->format('Y-m-d H:i:s'); // Outputs like '2017-03-14 00:00:00'

如果“ format”方法由于某种原因失败，它将返回FALSE，因此需要进行检查。

if (!$strDate) {
    $strDate = '1900-01-01 00:00:00';
}

Answer 2

$start_date = $_POST['start_date'];
$end_date = $_POST['end_date'];

$sdate = new DateTime($start_date . ' 00:00:00');
$edate = new DateTime($end_date   . ' 23:59:59');

$query = sprintf("select amount,date from pl_per_day where date between '%s' and '%s'",
    $sdate->format('Y-m-d H:i:s'),
    $edate->format('Y-m-d H:i:s')
);

Answer 3

您可以在查询本身中进行所有转换，如下所示。如果还需要时间比较，则可能必须将H：I：S部分添加到查询的$input = $mysqli->real_escape_string($_POST['input']); $sqlcheck = "SELECT * FROM questions WHERE word LIKE '%".$input."%' AND id = $pos"; $sqlresult = mysqli_query($mysqli, $sqlcheck);和$sdate中。

$edate

我想将日期转换为时间戳格式，以便可以将时间戳与存储的时间戳进行比较

3 个答案: