Question

我正在学习impacket，它是python2的一个模块，用于构建Internet应用程序，当我运行示例代码时，它得到一个错误号10022，这是我的代码，我想知道错误的原因。 / p>

我试图更改socket.socket的参数，我的英语不好，我的意思是我将IPPROTO_TCP更改为IPPROTO_IP，然后它停止出现错误，但是我无法捕获HTTP数据包。

import sys
import socket
from impacket import ImpactDecoder, ImpactPacket

def main(): 
    if len(sys.argv) < 3:
        print "Use: %s <src ip> <dst ip>" % sys.argv[0]
        print "Use: %s <src ip> <dst ip> <cnt>" % sys.argv[0]
        sys.exit(1)
    elif len(sys.argv) == 3:
        src = sys.argv[1]
        dst = sys.argv[2]
        cnt = 1
    elif len(sys.argv) ==4:
        src = sys.argv[1]
        dst = sys.argv[2]
        cnt = sys.argv[3]
    else:
        print "Input error!"
        sys.exit(1)
    print src, dst
    ip = ImpactPacket.IP()
    ip.set_ip_src(src)
    ip.set_ip_dst(dst)

    # Create a new ICMP packet of type ECHO.
    icmp = ImpactPacket.ICMP()
    tcp = ImpactPacket.TCP()
    tcp.set_th_sport(12138)
    tcp.set_th_dport(80)
    tcp.set_th_seq(1)
    tcp.set_th_ack(1)
    tcp.set_th_flags(0x18)
    tcp.set_th_win(64)

    tcp.contains( ImpactPacket.Data("GET / HTTP/1.1\r\nHost: 144.34.164.217\r\nAccept-Encoding: identity\r\n\r\n"))

    ip.contains(tcp)

    # Open a raw socket. Special permissions are usually required.
    s = socket.socket(socket.AF_INET, socket.SOCK_RAW, socket.IPPROTO_TCP)
    s.setsockopt(socket.IPPROTO_IP, socket.IP_HDRINCL, 1)
    seq_id = 0
    while cnt >= 1:
        # Calculate its checksum.
        seq_id = seq_id + 1
        tcp.set_th_seq(seq_id)
        tcp.calculate_checksum()

        # Send it to the target host.
        s.sendto(ip.get_packet(), (dst,80))
        cnt= cnt -1

if __name__ == '__main__':
    main()

我只想构建一个HTTP数据包

如何修复python impacket错误：Erroeno 10022

0 个答案: