Question

我正在使用Postgres 11，并具有以下SQL：

SELECT json_agg("Result"."record")
FROM (SELECT jsonb_build_object('emailAddress', "User"."emailAddress", 'displayName', "User"."displayName") as "record"
      FROM "User")
"Result"

，它会返回一行，如下所示：

[
  {"displayName": "Keith Stephens", "emailAddress": "kstephensqv@goo.gl"},
  {"displayName": "Robert Armstrong", "emailAddress": "rarmstrongrf@gooogle.es"}, 
  {"displayName": "Aaron Wagner", "emailAddress": "awagnerrh@cambo.ac.uk"}
]

我想要的是作为关联对象的结果：

{
  "kstephensqv@goo.gl": {"displayName": "Keith Stephens", "emailAddress": "kstephensqv@goo.gl"},
  "rarmstrongrf@gooogle.es": {"displayName": "Robert Armstrong", "emailAddress": "rarmstrongrf@gooogle.es"}, 
  "awagnerrh@cambo.ac.uk": {"displayName": "Aaron Wagner", "emailAddress": "awagnerrh@cambo.ac.uk"}
}

有什么方法可以仅使用Postgres SQL表达式来获得所需的结果吗？

Answer 1

因此，在发布了这个问题之后，我立即想到了一个想法，并提出了我想做的事情：

SELECT json_object_agg("Result"."key", "Result"."record")
FROM (SELECT "User"."emailAddress" as "key", jsonb_build_object('emailAddress', "User"."emailAddress", 'displayName', "User"."displayName") as "record"
      FROM "User") "Result"

返回JSON作为关联对象？

1 个答案: