使用jq将JSON对象转换为字符串数组

Question

我有一个JSON对象，它仅包含字符串和其他对象：

{
  "key1": "value1",
  "key2": "value2",
  "key3": {
    "subKey1":"value3",
    "subKey2":"value4"
  }
}

我想通过展平结构将其转换为字符串数组

[
  "key1.value1",
  "key2.value2",
  "key3.subKey1.value3",
  "key3.subKey2.value4",
]

我对jq语法还很陌生，到目前为止，我在的帮助下设法做到了这一点

to_entries | map([.key, .value | if type == "object" then type else . end]|join("."))

然后我得到

[
  "key1.value1",
  "key2.value2",
  "key3.object"
]

Answer 1

替代方法：

jq '[paths(scalars) as $p | $p + [getpath($p)] | join(".")]' f.json

预期输出：

[
  "key1.value1",
  "key2.value2",
  "key3.subKey1.value3",
  "key3.subKey2.value4"
]

Answer 2

使用paths使任务变得简单。

paths as $p
| getpath($p) 
| scalars
| $p + [.]
| join(".")

产生流：

"key1.value1"
"key2.value2"
"key3.subKey1.value3"
"key3.subKey2.value4"

因此，您需要将上方的过滤器括在方括号中以产生一个数组。