我需要一些帮助,因为我在定义变量以将其发布到Ajax时遇到问题。我正在使用PHP,因为我正在从mysql数据库中获取数据以在PHP中输入信息,因此我想将ID发布到ajax中。
我已经在while循环之外定义了变量$autoid
,但是当我使用jquery时我无法定义它们,因为当我尝试将它们发布到Ajax时它将显示空数据。
当我尝试这样做时:
var ID = $(this).data('deleteid');
$.ajax({
type: 'POST',
url: "sendtest.php",
data: {ID : "deleteid"
},
success: function(resultData) {
alert(resultData)
}
这是完整的代码:
<?php
// Initialize the session
session_start();
// Check if the user is logged in, if not then redirect him to login page
if(!isset($_SESSION["loggedin"]) || $_SESSION["loggedin"] !== true){
header("location: login.php");
exit;
}
else
{
$link = mysqli_connect('localhost', 'mydbusername', 'mydbpassword', 'mydbpassword');
$param_username = $_SESSION['username'];
$autocampaign = $_SESSION["auto_campaign"];
$autor_sql = "SELECT id, subject, day_cycle, enabled, delaysend FROM auto WHERE campaign ='$autocampaign' AND username ='$param_username'";
$autoid = '';
$results = mysqli_query($link, $auto_sql);
if (mysqli_num_rows($results) > 0)
{
while ($row = mysqli_fetch_array($results))
{
$autoid = $row["id"];
$autosubject = $row["subject"];
$autodaycycle = $row["day_cycle"];
$autoenabled = $row["enabled"];
$autodelay = $row["delaysend"];
}
}
?>
<!DOCTYPE html>
<html>
<head>
<meta name="viewport" content="width=device-width, initial-scale=1">
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.4/jquery.min.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/js/bootstrap.min.js"></script>
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/font-awesome/4.7.0/css/font-awesome.min.css">
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<style type="text/css">
.calendar-content {
float: left;
width: 100%;
min-height: 112px;
border: 1px solid #ccc;
position: relative;
margin-top: -1px;
}
</style>
<div class="calendar-content">
<div style="margin-left: 40px;margin-top: 20px; height: 40px;">
<span id="autosubject" style="font-size: 25px;color: #0c7ac0;float: left;">Subject: <?php echo $autosubject ?> </span><br>
<div style="margin-left: 35px; margin-top: 15px; height: 40px;">
<form action="" method="post">
<span style="font-size: 15px; color: #ccd5d9; float: left; margin-top: -1px"><a name="autoid" id="autoid" href="#contactModal" role="button" data-toggle="modal">Send a test</a> | <a name="deleteid" id="deleteid" href="/auto/delete_auto.php?id=<?php echo $autoid; ?>"> Delete </a> | Copy to Draft | Settings</span>
</form>
</div>
</div><br>
<!-- email Modal -->
<div id="contactModal" class="modal fade" style="margin-top: 12%;" tabindex="-1" role="dialog">
<div class="modal-dialog">
<!-- Modal content-->
<div class="modal-content" style="height: 250px;">
<div class="modal-header" style="margin-bottom: 10px;">
<button type="button" class="close" data-dismiss="modal">×</button>
<h3 class="modal-title">Send A Test Email</h3>
</div>
<div class="modal-body" style="height: 65%;">
<form action="" method="post">
<label class="label-control" value="">Send test message to email address:</label>
<select name="emails" id="emails" value="" style="width: 400px; margin-top: 10px; margin-bottom: 18px; margin-left: 60px;">
<option selected="selected" value='title'>Title</option>";
</select><br>
<button name="send_email" id="send_email" type="submit" class="btn btn-primary" style="margin-left: 36%;" data-auto-id="<?php echo $autoid; ?>">Send Test</button>
</form>
</div>
</div>
</div>
</div>
<script type="text/javascript">
$(function() {
$('#send_email').click(function(e) {
$(this)
.html("<span><i class='fa fa-spinner fa-spin'></i> Sending...</span>")
.prop("disabled", true);
var ID = $(this).data('deleteid');
$.ajax({
type: 'POST',
url: "sendtest.php",
data: {ID : "deleteid"
},
success: function(resultData) {
alert(resultData)
$('#contactModal').modal('hide');
$("#send_email")
.html("Send Test")
.prop("disabled", false);
}
});
});
});
</script>
<?php
}
?>
这是sendtest.php:
<?php
// Initialize the session
session_start();
// Check if the user is logged in, if not then redirect him to login page
if(!isset($_SESSION["loggedin"]) || $_SESSION["loggedin"] !== true){
header("location: login.php");
exit;
}
else if(isset($_POST))
{
$id = $_POST[$autoid];
echo "hello your id is...";
echo $id;
}
?>
我想要实现的是,当我单击发送测试超链接时,将显示一个模式,并且当我在下拉列表框中选择后单击按钮时,我想从“删除”超链接中获取ID,所以我可以将它们发布在ajax中。我想在ajax中发布ID的原因是,当我想从mysql数据库中获取信息时,我希望停留在同一页面上。
能否请您举一个例子,说明如何从“删除”超链接中获取ID并将其发布到ajax中?
谢谢您了解我要做什么。
答案 0 :(得分:1)
您的代码中存在几个问题:
第一:data: {ID : "deleteid"},
应该是data: {ID : ID },
(您要发送var,而不是字符串“ deleteid”)
2nd:var ID = $(this).data('deleteid');
应该是var ID = $(this).data('auto-id');
,因为数据属性是data-auto-id =“ ...
3rd:$id = $_POST[$autoid];
将引发错误(未定义的变量)和通知(未定义的索引)。应该为$id = $_POST['ID']
,因为您在此处将参数称为“ ID”:data: {ID : varname},
第四:您在这里缺少;
:alert(resultData)
这是更正的ajax部分:
var ID = $(this).data('auto-id');
$.ajax({
type: 'POST',
url: "sendtest.php",
data: {ID : ID },
success: function(resultData) {
alert(resultData);
$('#contactModal').modal('hide');
$("#send_email")
.html("Send Test")
.prop("disabled", false);
}
});