我只想要该图像位于指定的列(位于“国家/地区”列中)而不是第一列中。谢谢!
from tkinter import ttk
from tkinter import *
root = Tk()
s = ttk.Treeview(columns=('#1', '#2'))
s.heading('#0', text='Ip')
s.heading('#1', text='Port')
s.heading('#2', text='Country')
s.pack()
v = PhotoImage(file='uk.png')
s.insert('', 2, values=('127.0.0.1', '8888'), image=v)
root.mainloop()
答案 0 :(得分:0)
我已经很简单了:)只是从国家开始
from tkinter import ttk
from tkinter import *
root = Tk()
s = ttk.Treeview(columns=('#1', '#2'))
s.heading('#0', text='Country')
s.heading('#1', text='Ip')
s.heading('#2', text='Port')
v = PhotoImage(file='uk.png')
s.insert('', 2, values = ('127.0.0.1', '8888'), image=v)
s.pack()
root.mainloop()
from tkinter import ttk
from tkinter import *
root = Tk()
v = PhotoImage(file='uk.png')
# header
b = Label(root, text="Ip")
b.grid(row=0, column=0)
b = Label(root, text="port")
b.grid(row=0, column=1)
b = Label(root, text="Country")
b.grid(row=0, column=2)
lista = [["800","127.1.1.",v]]
height = 2
width = 3
for i in range(height-1): #Rows
b1 = Label(root, text=lista[i][0])
b1.grid(row=i+1, column=0)
b2 = Label(root, text=lista[i][1])
b2.grid(row=i+1, column=1)
b3 = Label(root, image=lista[i][2])
b3.grid(row=i+1, column=2)
mainloop()