Question

这是我创建帐户的代码，但是当已经注册了电子邮件ID时，应用崩溃了，而我的try catch方法无法捕获它。如何解决这个问题？

void careteAccount() async {
if (in_email.text.trim().length > 0 && in_password.text.trim().length > 0) {
  try {
    //   FirebaseAuth.instance.verifyPhoneNumber(phoneNumber: "+919656936681", codeAutoRetrievalTimeout: (String verificationId) {}, codeSent: (String verificationId, int forceResendingToken) {}, timeout: null, verificationCompleted: (FirebaseUser firebaseUser) {}, verificationFailed: (AuthException error) {});

    FirebaseUser user = await FirebaseAuth.instance
        .createUserWithEmailAndPassword(
            email: in_email.value.text.trim(), password: in_password.value.text.trim())
            .catchError((e){
              print(e.toString());
              Fluttertoast.showToast(
        msg: e.toString(),
        toastLength: Toast.LENGTH_SHORT,
        gravity: ToastGravity.TOP,
        timeInSecForIos: 1,
        backgroundColor: Colors.black54,
        textColor: Colors.white);
            })
            .then((u){
              if(u!=null?u.email!=null?true:false:false){
                print("account created "+u.email);
              }else{
                print("account creatin failed");
              }
            });
    print("create accound in ${user.email}");
  } catch (e) {
    print(e.toString());
    Fluttertoast.showToast(
        msg: e.toString(),
        toastLength: Toast.LENGTH_SHORT,
        gravity: ToastGravity.TOP,
        timeInSecForIos: 1,
        backgroundColor: Colors.black54,
        textColor: Colors.white);
    print('Error $e');
  }
} else {
  print("login called and countroler is null");
}}

错误消息“给定的密码无效。[密码至少应包含6个字符]”

我需要以编程方式找出错误，而不是上面的图像

D /（8896）：HostConnection :: get（）建立新的主机连接0xb40f0c90，tid 8923 D / EGL_emulation（8896）：     eglMakeCurrent：0xb42bc4c0：ver 2 0 W / BiChannelGoogleApi（8896）：     [FirebaseAuth：] getGoogleApiForMethod（）返回了Gms：     com.google.firebase.auth.api.internal.zzal@3b1fc27b

成功创建帐户时出错

I/flutter ( 9012): account created milla@gmail.com
Unhandled exception:
NoSuchMethodError: The getter 'className' was called on null.
Receiver: null
Tried calling: className
#0      Object.noSuchMethod (dart:core/runtime/libobject_patch.dart:50:5)
#1      serializeProcedure (package:front_end/src/fasta/kernel/utils.dart:99:29)
#2      FrontendCompiler.compileExpression (package:vm/frontend_server.dart:482:16)
<asynchronous suspension>
#3      _FlutterFrontendCompiler.compileExpression (package:frontend_server/server.dart:62:22)
#4      listenAndCompile.<anonymous closure> (package:vm/frontend_server.dart:797:20)
<asynchronous suspension>
#5      _RootZone.runUnaryGuarded (dart:async/zone.dart:1314:10)
#6      _BufferingStreamSubscription._sendData (dart:async/stream_impl.dart:336:11)
#7      _BufferingStreamSubscription._add (dart:async/stream_impl.dart:263:7)
#8      _SinkTransformerStreamSubscription._add (dart:async/stream_transformers.dart:68:11)
#9      _EventSinkWrapper.add (dart:async/stream_transformers.dart:15:11)
#10     _StringAdapterSink.add (dart:convert/string_conversion.dart:268:11)
#11     _LineSplitterSink._addLines (dart:convert/line_splitter.dart:154:13)
#12     _LineSplitterSink.addSlice (dart:convert/line_splitter.dart:129:5)
#13     StringConversionSinkMixin.add (dart:convert/string_conversion.dart:189:5)
#14     _SinkTransformerStreamSubscription._handleData (dart:async/stream_transformers.dart:120:24)
#15     _RootZone.runUnaryGuarded (dart:async/zone.dart:1314:10)
#16     _BufferingStreamSubscription._sendData (dart:async/stream_impl.dart:336:11)
#17     _BufferingStreamSubscription._add (dart:async/stream_impl.dart:263:7)
#18     _SinkTransformerStreamSubscription._add (dart:async/stream_transformers.dart:68:11)
#19     _EventSinkWrapper.add (dart:async/stream_transformers.dart:15:11)
#20     _StringAdapterSink.add (dart:convert/string_conversion.dart:268:11)
#21     _StringAdapterSink.addSlice (dart:convert/string_conversion.dart:273:7)
#22     _Utf8ConversionSink.addSlice (dart:convert/string_conversion.dart:348:20)
#23     _Utf8ConversionSink.add (dart:convert/string_conversion.dart:341:5)
#24     _ConverterStreamEventSink.add (dart:convert/chunked_conversion.dart:86:18)
#25     _SinkTransformerStreamSubscription._handleData (dart:async/stream_transformers.dart:120:24)
#26     _RootZone.runUnaryGuarded (dart:async/zone.dart:1314:10)
#27     _BufferingStreamSubscription._sendData (dart:async/stream_impl.dart:336:11)
#28     _BufferingStreamSubscription._add (dart:async/stream_impl.dart:263:7)

Answer 1

在Firebase中，密码必须至少包含6个字符。

Answer 2

为了使代码更安全，避免抛出异常，您必须在firebase中创建身份验证帐户或也登录时检查代码是否将其抛出

例如在您的州使用此方法，例如，在您的FirebaseAuthUtil class中添加此方法

static Future<dynamic> createEmailAndPassword(String email,String pass) async{

    FirebaseAuth mAuth = FirebaseAuth.instance;


    try {
      AuthResult result =await mAuth.createUserWithEmailAndPassword(email: email, password: pass);

      FirebaseUser userFirebase = await mAuth.currentUser();
      if (userFirebase != null && result.user.uid == userFirebase.uid) {
        return userFirebase;
      } else {
        return PlatformException(code: "-1", message: "error assign uid");
      }
    } on PlatformException catch (ex) {
      debugPrint("ex :${ex.code}");
      return ex;
    }

并从您的注册页面调用上述方法

dynamic result = FirebaseAuthUtil.createEmailAndPassword(email, pass);

    if(result is FirebaseUser ){
      // create account is success
    }else if(result is PlatformException){
      debugPrint("ereor signUp :${result.code}");
    }

尝试使用电子邮件和密码创建帐户时，Flutter应用程序崩溃了

2 个答案: