Question

问题是将非ASCII字符转换为二进制字符，反之亦然

string of bits to string of char
string result = "";
            while (value.Length > 0)
            {   var first8 = value.Substring(0, 8);
                value = value.Substring(8);
                var number = Convert.ToInt64(first8, 2);
                result += (char)number;

和字符字符串到位字符串

string S = "";
            byte[] asciiBytes = Encoding.ASCII.GetBytes(value);
            for (int i = 0; i < asciiBytes.Length; i++)
                for (int j = 0; j < 8; j++)
                {
                    S += (asciiBytes[i] & 0x80) > 0 ? "1" : "0";
                    asciiBytes[i] <<= 1;
                }
            return S;

如果我的代码最好，您可以更正吗？

Answer 1

您可以将字符串拆分为8个字符串，使用Convert.ToByte将其转换为字节，然后使用Encoding.ASCII.GetString将字节数组转换为字符串。

var str = "0011111110110101001111110110111100111111110110110011111101101111";
var byteArray = Enumerable.Range(0, str.Length / 8)
        .Select(x => Convert.ToByte(str.Substring(x * 8, 8), 2)).ToArray();
var convertedString = Encoding.ASCII.GetString(byteArray);

对于8位

Encoding enc = Encoding.GetEncoding(1252);
var convertedString = enc.GetString(byteArray);

输出

?µ?o?Û?o

在字符串位和字符串char之间转换为ASCII

1 个答案: