Question

虽然遍历列表中的所有元素，但我想在遇到特定元素时跳过后面的两个元素，例如：

l1 = ["a", "b", "c", "d", "e", "f"]
for index, element in enumerate(l1):
    if element == "b":
        index = index + 2
    else:
        print(index, element)

0 a
2 c
3 d
4 e
5 f

Answer 1

更改索引将无法进行，因为它是由枚举迭代器创建的。您可以自己在迭代器上调用next()：

l1 = ["a", "b", "c", "d", "e", "f"]

iter  = enumerate(l1)
for index, element in iter:
    if element == "b":
        next(iter, None) # None avoids error if b is at the end
    else:
        print(index, element)

0 a
  3天
  4 e
  5楼

Answer 2

l1 = ["a", "b", "c", "d", "e", "f"]
index = 0
while index < len(l1):
    if l1[index] == "b":
        index += 2
    else:
        print(index, l1[index])
        index += 1


0 a
3 d
4 e
5 f

可以使用while循环。 index += 1，如果您要2 c

如果条件增加列表索引

2 个答案: