Question

当我直接使用Python（开发模式？）运行Flask应用程序时，一切正常，因此，templates文件夹位于正确的位置。当我通过Gunicorn运行它时，它始终无法找到我的模板文件夹，因此找不到所需的HTML文件。我尝试了很多事情，例如更改template_folder变量以及传递给render_template()的路径-没有任何影响。

我从gunicorn -b 0.0.0.0:80 wsgi开始使用gunicorn（如果没有wsgi，它仍然无法使用），一切正常。

端子：

root@vps621912:/home/websites/test2# source test2/bin/activate
(test2) root@vps621912:/home/websites/test2# gunicorn -b 0.0.0.0:80 server:app
[2018-12-21 18:13:55 +0000] [30377] [INFO] Starting gunicorn 19.9.0
[2018-12-21 18:13:55 +0000] [30377] [INFO] Listening at: http://0.0.0.0:80 (30377)
[2018-12-21 18:13:55 +0000] [30377] [INFO] Using worker: sync
[2018-12-21 18:13:55 +0000] [30381] [INFO] Booting worker with pid: 30381
[2018-12-21 18:14:00,240] ERROR in app: Exception on / [GET]
Traceback (most recent call last):
  File "/home/websites/test2/test2/local/lib/python2.7/site-packages/flask/app.py", line 2292, in wsgi_app
    response = self.full_dispatch_request()
  File "/home/websites/test2/test2/local/lib/python2.7/site-packages/flask/app.py", line 1815, in full_dispatch_request
    rv = self.handle_user_exception(e)
  File "/home/websites/test2/test2/local/lib/python2.7/site-packages/flask/app.py", line 1718, in handle_user_exception
    reraise(exc_type, exc_value, tb)
  File "/home/websites/test2/test2/local/lib/python2.7/site-packages/flask/app.py", line 1813, in full_dispatch_request
    rv = self.dispatch_request()
  File "/home/websites/test2/test2/local/lib/python2.7/site-packages/flask/app.py", line 1799, in dispatch_request
    return self.view_functions[rule.endpoint](**req.view_args)
  File "/home/websites/test2/server.py", line 10, in home
    return render_template('home.html')
  File "/home/websites/test2/test2/local/lib/python2.7/site-packages/flask/templating.py", line 134, in render_template
    return _render(ctx.app.jinja_env.get_or_select_template(template_name_or_list),
  File "/home/websites/test2/test2/local/lib/python2.7/site-packages/jinja2/environment.py", line 869, in get_or_select_template
    return self.get_template(template_name_or_list, parent, globals)
  File "/home/websites/test2/test2/local/lib/python2.7/site-packages/jinja2/environment.py", line 830, in get_template
    return self._load_template(name, self.make_globals(globals))
  File "/home/websites/test2/test2/local/lib/python2.7/site-packages/jinja2/environment.py", line 804, in _load_template
    template = self.loader.load(self, name, globals)
  File "/home/websites/test2/test2/local/lib/python2.7/site-packages/jinja2/loaders.py", line 113, in load
    source, filename, uptodate = self.get_source(environment, name)
  File "/home/websites/test2/test2/local/lib/python2.7/site-packages/flask/templating.py", line 58, in get_source
    return self._get_source_fast(environment, template)
  File "/home/websites/test2/test2/local/lib/python2.7/site-packages/flask/templating.py", line 86, in _get_source_fast
    raise TemplateNotFound(template)
TemplateNotFound: home.html

代码：

from flask import Flask, render_template


app = Flask('__main__', template_folder='../../')


@app.route('/')
def home():
#    return "<h1>test2 - server.py - raw return</h1>"
    return render_template('home.html')
#    return app.root_path


if __name__ == '__main__':
    app.run(host='0.0.0.0', debug=True)

任何帮助表示赞赏。

Answer 1

赋予Flask的第一个参数用于在文件系统上查找资源。在您的情况下，您正在传递__main__，如果应用程序的入口点为server.py或称为开发模式，则很好。如果您使用gunicorn运行应用程序，那么您的server.py脚本将不再是入口点；这意味着无法将__main__传递到Flask。请改用以下内容：

application = Flask(__name__, template_folder='../../')

当脚本是python解释器的入口点时，Python会将__name__设置为'__main__'。否则，它将评估为模块的名称。另外，请注意，如果未在gunicorn命令中指定应用名称，则必须使用application而不是app。

如果您使用软件包而不是单个模块来运行您的应用程序，则此方法可能不起作用。您可以找到更多信息here。

通过Gunicorn运行时，烧瓶无法在模板文件夹中找到HTML文件

1 个答案: