Question

我使用Angular试图将一个大型函数分离为多个较小的函数。使用以下内容：

from M2Crypto import RSA, X509
x509 = X509.load_cert("your_cert.pem")
rsa = x509.get_pubkey().get_rsa()

# building a secret as a 32bytes bytearray
my_secret = "This is my secret, and nobody knows it"
my_secret_bin = bytearray(my_secret)
# this should be exactly 32
len(my_secret_bin)

import base64
import hashlib

my_hash = base64.b64encode((hashlib.sha256(my_secret_bin[0:32])).digest())              
my_encrypted_secret = base64.b64encode(rsa.public_encrypt(my_secret_bin[0:32], RSA.pkcs1_oaep_padding))    

# This can be used to call it via API
# note that the 'your_cert' certificate name should match
upload_params = { 'SecretValue':my_encrypted_secret, 'SecretValueHash':my_hash, 'SecretValueCertificate':'your_cert'}


# write to files
with open('encrypted_secret.bb64', 'wb') as f:
f.write(my_encrypted_secret)

with open('secret_hash.b64', 'wb') as f:
f.write(my_hash)

但是，在getSites() { this.http.get(`https://example.com/dev/_api/web/lists/getbytitle('Site Master')/items?$select=*,Hub/Title&$expand=Hub&$filter=Hub/Title eq 'Project Hub' and Active eq 'Yes'`).subscribe(data => { console.log(`project sites`, data['value']) this.sites = data['value'] this.getLists() //Wait for this.sites to populate, then fire }) } getLists() { this.sites.forEach(site => { this.http.get(`${site['Site']}/_api/web/lists/?$select=*&$filter=BaseTemplate eq 171`).subscribe(data => { console.log("Site's lists", data['value']) this.getTasks(data['value'], site) }) }) }可以从第一个请求中完全填充之前，getLists()正在触发。我该怎么解决？

Answer 1

您可以使用concatMap管道（这将等待getSites完成），而不是同时订阅这两个功能

getSites():Observable<any>{
    this.http(...).pipe(map(() => ....)
}
getList(): Observable<any>{
    // do some stuff
}

// and use it like this 
getSites().pipe(contactMap((getSiteResult) => getList(getSiteResult)).subscribe()

希望有帮助

响应后调用功能

1 个答案: